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Lady_Fox [76]
2 years ago
13

When 400 J of heat are slowly added to 10 mol of an ideal monatomic gas, its temperature rises by 10°C. What is the work done on

the gas?
Chemistry
1 answer:
Molodets [167]2 years ago
7 0

When 400 J of heat are slowly added to 10 mol of an ideal monatomic gas, its temperature rises by 10°C. The work done on the gas is 845J.

The amount of work done on gas depends upon the internal energy change and the heat supplied to the system.

According to First Law of Thermodynamics, the change in internal energy is equal to the work done and the heat supplied to the system.

This is given by:

ΔU = W + Q

where, ΔU is change in Internal energy

            W is the Work done

            Q is the heat supplied

Given,

Q = 400J

Number of moles, n = 10

Change in temperature, ΔT = 10°C

Cv = 3/2R ; Since, the given gas is monoatomic (R=8.3)

We know that, ΔU = n Cv ΔT

On substituting the values in above formula,

ΔU = 10 × 3/2 × 8.3 × 10

ΔU = 1245J

Using,

ΔU = W + Q

1245J = W + 400

W = 845J

Hence, the work done on the gas is 845J.

Learn more about Thermodynamics here, brainly.com/question/1368306

#SPJ4

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Mashutka [201]
<h3>Answer:</h3>

12.387 moles

<h3>Explanation:</h3>

We are given;

Temperature of chlorine, T = 120°C

But, K = °C + 273.15

Therefore, T = 393.15 K

Pressure, P = 33.3 Atm

Volume, V = 12 L

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To find the number of moles we are going to use the ideal gas equation;

PV = nRT

R is the ideal gas constant, 0.082057 L.atm/mol.K

Therefore, rearranging the formula;

n = PV÷RT

Hence;

n = (33.3 atm × 12 L) ÷ (0.082057 × 393.15 K)

  = 12.387 moles

Therefore, the number of moles of chlorine are 12.387 moles

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