Let, coordinate of point A' is (x,y).
Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.
So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.
Now, their center is given by :
Also, product of slope will be -1 .( Since, they are parallel )
x = 2y - 1
So, 
Also, C satisfy given line :
Also,
Therefore, the symmetric points is
.
The awser for this problem im preety sure is going to be aswer c
Answer:
3x^2 + 16x + 42
3x^2 + 4x + 2
3x^2 – 16x + 42
3x^2 – 4x + 2
Step-by-step explanation:
Answer:
x=1
Step-by-step explanation:
1. Complete the square on the right side of the equation.
5
(
x
−
1
)2
−
18
2. Use the vertex form, y
=
a
(
x
−
h
)
2
+
k
, to determine the values of a
, h
, and k
.
a=
5
h
=
1
k
=
−
18
3. Since the value of a is positive, the parabola opens up.
Opens Up
4. Find the vertex (
h
,
k
)
.
(
1
,
−
18
)
5. Find p
, the distance from the vertex to the focus.
1
/20
6. Find the focus.
7. (
1
,
−
359/
20
)
8. Find the axis of symmetry by finding the line that passes through the vertex and the focus.
ANSWER: x
=
1
Collinear points lie on the same line. So, you must look for other points that lie on the line that connects A and N. If you start from A and continue along that line, you can see that, after N, you will meet points M and F.
So, those points are collinear with A and N.
