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Simora [160]
3 years ago
10

(9x-3 1/8)- (7x+1 3/8)

Mathematics
1 answer:
Rom4ik [11]3 years ago
5 0
*\\(9x-3\frac{1}{8})-(7x+1\frac{3}{8})=\ \ \ |Omit\ the\ brackets\\\\
(9x-3\frac{1}{8})-(7x+1\frac{3}{8})=9x-3\frac{1}{8}-7x-1\frac{3}{8}=\ \ \ \ \ |add\ similar\ factors\\\\
\boxed{2x-4\frac{1}{2}}
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Assuming the cylinder is closed at both ends 
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JulsSmile [24]
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3 years ago
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Firdavs [7]

We are given :

\sqrt{4x^{2}-20x+25}

Step 1: factor the part inside square root

The function given inside square root is of quadratic form.

So let us try to factorise it using AC method.

Here A*C = 4*25 = 100

so we have to find factors of 100 that add up to give -20.

the two factors are -10 and -10.

Rewriting the function :

4x^{2} -20x+25

=4x^{2} -10x-10x+25

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Step 2:

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= 2x-5

Answer : (2x-5)

3 0
3 years ago
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