4 years ago

(9x-3 1/8)- (7x+1 3/8)

1 answer:

5 0

$*\\(9x-3\frac{1}{8})-(7x+1\frac{3}{8})=\ \ \ |Omit\ the\ brackets\\\\
(9x-3\frac{1}{8})-(7x+1\frac{3}{8})=9x-3\frac{1}{8}-7x-1\frac{3}{8}=\ \ \ \ \ |add\ similar\ factors\\\\
\boxed{2x-4\frac{1}{2}}$

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