What is (p^2-6p-5)(3p^2-7p-4) in standard form

Rachel wants to put mulch around her three raised flower beds, as shown in the figure below,

shutvik [7]

Answer:

hold up kiddo I need to check it real quick

5 0

3 years ago

Test scores: Scores on a statistics exam had a mean of 75 with a standard deviation of 5. Scores on a calculus exam had a mean o

beks73 [17]

Answer:

CV for statistics exam = 15%

CV for calculus exam = 19%

Since the CV for calculus exam is higher, it has a greater spread relative to the mean than the statistics exam.

Step-by-step explanation:

To find coefficient variation we use the formula:

CV = (SD/mean) * 100

CV for the statistics exam:

where; SD= 5

mean= 75

CV = ( 5/75) *100

= 0.15 or 15%

CV for calculus exam

SD = 11

Mean= 58

CV= (11 /58) * 100

= 0.19 or 19%

8 0

3 years ago

2/3x+5=1 what is the solution to the equation shown?

Fudgin [204]

Answer:

x = - 6

Step-by-step explanation:

Given

$\frac{2}{3}$ x + 5 = 1 ( subtract 5 from both sides )

$\frac{2}{3}$ x = - 4

Multiply both sides by 3 to clear the fraction

2x = - 12 ( divide both sides by 2 )

x = - 6

7 0

4 years ago

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Scale drawing of the electronics board

lora16 [44]

Area of the electronic board is 9000 cm2

Step-by-step explanation:

Write ratios to represent the unknown actual length and width of the display to the scale length and width of the display.

The Electronic board always seems like a rectangular shape

Length= scale÷Actual = 5/36 = 5×36 = 180cm

$Length= scale÷Actual = 5/36 = 5×36 = 180cm$

Width=scale÷Actual = 1/50 = 1×50 = 50cm

$Width=scale÷Actual = 1/50 = 1×50 = 50cm$

Area of Rectangle = legnth × width

= 180cm × 50cm = 9000 cm2

$= 180cm × 50cm = 9000 cm2$

Area of the electronic board is 9000 cm2

6 0

3 years ago

Can you help with this please.

andrew-mc [135]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - two points P ( 5 , 10 ) and R ( 12 , 14 ) on the cartesian plane

To find - distance between the two points

Using the distance formula ~

$\qquad\underline{d(PR) = \sqrt{( x_{2} - x_{1}) {}^{2} + ( y_{2} - y_{1}) {}^{2} }} \\ \\$

we have ,

$\longrightarrow x_{1} = 5 \\ \longrightarrow x_{2} = 12 \\ \\ \longrightarrow \: y_{1} = 10 \\ \longrightarrow \: y_{2} = 14$

substituting the values in the formula , we get

$d(PR) = \sqrt{(12-5) {}^{2} + (14-10) {}^{2} } \\ \\ \implies \: d(PR) = \sqrt{(7) {}^{2} + ( 4) {}^{2} } \\ \\ \implies \: d(PR) = \sqrt{49 + 16} \\ \\ \implies \: d(PR) = \sqrt{65} \\ \\ \implies \: d(PR) = 8.1 \: units \: (approx)$

hope helpful :)

5 0

2 years ago

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