Answer:
Explanation:
<u>Given:</u>
- Charge on each corner of the square,
- Length of the side of the square,
According to the Coulomb's law, the strength of the electric field at a point due to a charge at a point distance away is given by
where,
= Coulomb's constant = .
The direction of the electric field is along the line joining the point an d the charge.
The electric field at the point P due to charge at A is given by
Since, this electric field is along positive x axis direction, therefore,
is the unit vector along the positive x-axis direction.
The electric field at the point P due to charge at B is given by
Since, this electric field is along negative y axis direction, therefore,
is the unit vector along the positive y-axis direction.
The electric field at the point P due to charge at C is given by
where, .
Since, this electric field is along the direction, which is making an angle of below the positive x-axis direction, therefore, the direction of this electric field is given by .
Thus, the total electric field at the point P is given by
The magnitude of the electric field at the given point due to all the three charges is given by