Answer:

Explanation:
Given:
- time taken by the sun to complete one revolution,

- radial distance of the sunspot,

<u>Therefore, angular speed of rotation of sun:</u>

<u>Now the tangential velocity of the sunspot can be given by:</u>



Answer:
The net gravitational force on the mass is 
Explanation:
We have by Newton's law of gravity the force of attraction between masses 

Applying vales we get
Force of attraction between 135 kg mass and 38 kg mass is

Force of attraction between 435 kg mass and 38 kg mass is

Thus the net force on mass 38.0 kg is 
The computation would be:moles = mass/ Molar Mass, but we are looking for the mass, so rearranging, will give us: mass = moles x MM
Q = moles x Hf
Q = (mass/MM) x Hf
mass = (Q x MM) / Hf
= (1.50-kJ x 18.0-g/mol) / 6.01-kJ/mol
=4.49 g H20 is the answer
Answer:
Can you explain more in detail what it is?
Explanation:
Answer:
ΔU=0.8834 Btu
Explanation:
Given data
Area of piston A=40 in²
The weight W=100 lbf
Atmospheric Pressure P=14.7 lbf/in²
Work added E=3 Btu
The change in elevation Δh=1 ft =12 inch
To find
Change in internal energy of the gas ΔU
Solution
For Piston
ΔPE=| W+(P×A)×Δh |
ΔPE=| 100+(14.7×40)×12 |
ΔPE=8256 lbf.in
ΔPE=8256×0.000107
ΔPE=0.8834 Btu
From law of conservation of energy then ,the charging in the potential energy of the piston is made by exerting force by gas
Wgas= -ΔPE
Wgas= -0.8834 Btu
For the gas as a system and by applying first law of thermodynamics
Q-W=ΔU
0-(-0.8834 Btu)=ΔU
So
ΔU=0.8834 Btu