The force of gravity is less between two objects that

What are the different types of Energy transformations and Energy Transfers?

Harman [31]

Explanation:

Here are some of the ways that energy can change (transform) from one type to another:

The Sun transforms nuclear energy into heat and light energy.

Our bodies convert chemical energy in our food into mechanical energy for us to move.

An electric fan transforms electrical energy into kinetic energy.

7 0

4 years ago

A circular loop of wire lies in the plane of your screen. An increasing magnetic field (produced by another source) points out o

Rashid [163]

Answer:

clockwise direction

Explanation:

Direction of induced current is found with the help of Lenz's law . According to this law , the direction of induced current is such that it tries to neutralize or oppose the reason which creates this current .

In the given case , magnetic field is towards the viewer of the screen and it is increasing , so the induced current will have to create magnetic field in opposite to it . It means magnetic field will be created towards the screen into it . So the current will be induced in clockwise direction . This current will create magnetic field into the screen which will oppose increasing magnetic field out of screen .

7 0

3 years ago

In the expression 3x2y + 4x – 5x2y, are the terms 3x2y and –5x2y like terms? Explain by providing support for your answer.

Zanzabum

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3 0

3 years ago

Read 2 more answers

A particle moves along the x-axis according to x(t)=10t−2t²m. (a) What is the instantaneous velocity at t = 2 s and t = 3 s? (b)

Alisiya [41]

Answer:

a) v(2) = 2m/s, v(3) = -2m/s

b) speed at t = 2s is 2m/s

speed at t = 3s is 2m/s

c) 0 m/s

Explanation:

We can take the derivative of x(t) to find the equation of velocity

v(t) = x'(t) = 10 - 4t

(a) v(2) = 10 - 4*2 = 10 - 8 = 2 m/s

v(3) = 10 - 4*3 = 10 - 12 = -2 m/s

(b) The speed would be the same as velocity without the direction

speed at t = 2s is 2m/s

speed at t = 3s is 2m/s

(c) The average velocity between t = 2s and t = 3s is distance it travels over period of time

$v_a = \frac{s(3) - s(2)}{\Delta t} = \frac{10*3 - 2*3^2 - (10*2 - 2*2^2)}{3 - 2}$

$v_a = \frac{12 - 12}{1} = 0/1 = 0 m/s$

6 0

3 years ago

In class we described the tidal forces that are responsible for raising and lowering thewater level near the shore of the ocean.

Sloan [31]

The newton's law of universal gravitation used to describe how a particle attracts every other particle in the universe.

The equation is given by,

$F= G\frac{m_1 m_2}{r_2}$

Where,

F= Gravitational force

$m_1, m_2 =$ masses of the objects

r= is the distance between the center of their masses

G= Gravitational constant

For our problem we have defined that,

$M_m = 7.24*10^{22}kg$ (mass of the moon)

$d= 3.84*10^8 km$ (distance Earth-moon)

G= 6.671*10^{-11}Nm^2/kg^2

M=Mass of a person

We have then,

$F_m = M\frac{6.67*10^-11*7.34*10^22}{3.84*10^8}$

$F_m = M*3.320*10^{-5} N$

In the other hand we have the force on m-mass due to earth

$F_E= MG = M*9.8N$

Ratio is given by

$\frac{F_m}{F_E} = {M*3.320*10^{-5}}{9.8} = 3.387*10^{-6}$

B) Suppose there is a group of young people surfing in the moonlight. They are directly under the moon. At this time the moon exerts its gravitational effect of the earth that causes the tide to rise. Around 6 hours later, when the earth has moved a quarter of the moon, the force on that point decreases, so the tide drops. However, after another 6 hours, people return and experience the same process. In this case the moon is not above them, but on the other side. This is because the moon having an orbit on the earth, generates an external force, similar to the previous one, but the earth reacts in the opposite way. It is like going in a car and turning it, all people will tend to get out of it, because a centrifugal force is experienced.

7 0

4 years ago