Explanation:
It is given that,
Mass of Millersburg Ferry, m = 13000 kg
Velocity, v = 11 m/s
Applied force, F = 10⁶ N
Time period, t = 20 seconds
(a) Impulse is given by the product of force and time taken i.e.
![J=F.\Delta t](https://tex.z-dn.net/?f=J%3DF.%5CDelta%20t)
![J=10^6\ N\times 20\ s](https://tex.z-dn.net/?f=J%3D10%5E6%5C%20N%5Ctimes%2020%5C%20s)
![J=2\times 10^7\ N-s](https://tex.z-dn.net/?f=J%3D2%5Ctimes%2010%5E7%5C%20N-s)
(b) Impulse is also given by the change in momentum i.e.
![J=\Delta p=p_f-p_i](https://tex.z-dn.net/?f=J%3D%5CDelta%20p%3Dp_f-p_i)
![J=p_f-p_i](https://tex.z-dn.net/?f=J%3Dp_f-p_i)
![p_f=J+p_i](https://tex.z-dn.net/?f=p_f%3DJ%2Bp_i)
![p_f=2\times 10^7\ N-s+13000\ kg\times 11\ m/s](https://tex.z-dn.net/?f=p_f%3D2%5Ctimes%2010%5E7%5C%20N-s%2B13000%5C%20kg%5Ctimes%2011%5C%20m%2Fs)
![p_f=20143000\ kg-m/s](https://tex.z-dn.net/?f=p_f%3D20143000%5C%20kg-m%2Fs)
(c) For new velocity,
![v_f=\dfrac{p_f}{m}](https://tex.z-dn.net/?f=v_f%3D%5Cdfrac%7Bp_f%7D%7Bm%7D)
![v_f=\dfrac{20143000\ kg-m/s}{13000\ kg}](https://tex.z-dn.net/?f=v_f%3D%5Cdfrac%7B20143000%5C%20kg-m%2Fs%7D%7B13000%5C%20kg%7D)
![v_f=1549.46\ m/s](https://tex.z-dn.net/?f=v_f%3D1549.46%5C%20m%2Fs)
Hence, this is the required solution.
Answer:
20.7N
Explanation:
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The answer is NOT covalent , it is Hydrogen .
Explanation:
It is given that,
Let Charge of
is taken from points A & B such that
.
We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,
![W=(V_B-V_A)q\\\\W=-1000\times 10^{-6}\\\\W=E=-10^{-3}\ J](https://tex.z-dn.net/?f=W%3D%28V_B-V_A%29q%5C%5C%5C%5CW%3D-1000%5Ctimes%2010%5E%7B-6%7D%5C%5C%5C%5CW%3DE%3D-10%5E%7B-3%7D%5C%20J)
So, the energy of charge decreases by
. Hence, the correct option is (a).