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Thepotemich [5.8K]
3 years ago
5

What would the equation be?

Mathematics
1 answer:
denis-greek [22]3 years ago
4 0
Where’s the equation??
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What are the two solutions of 2x^2 = -X^2 - 5x - 1?
Sidana [21]

Answer:

Step-by-step explanation:

Let's solve 2x^2 = -X^2 - 5x - 1.  Consolidate all terms on the left side and write 0 on the right side:

3x^2 + 5x + 1 = 0.  This is a quadratic equation.  Let's solve it for x using the quadratic formula:

a = 3, b = 5, c = 1, and so the discriminant is b^2 - 4ac = 5^2 - 4(3)(1) = 13.  Because the discriminant is positive, we know that there are two distinct, real roots; the graphs of y = 2x^2 and y = x^2 - 5x - 1 intersect in two places whose x-coordinates are the real roots mentioned above.

Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."  

Answer C would be correct if and only if we write y = x^2 - 5x - 1.

6 0
4 years ago
How to do multiplication large numbers.
Keith_Richards [23]

Answer:

The main reason to know the multiplication table is so you can more easily multiply larger numbers. For example, suppose you want to multiply 53 x 7. Start by stacking these numbers on top of another, aligning the ones place. Draw a line underneath, and then multiply 3 by 7. Because 3 x 7 = 21, write down the ones digit (1) and carry the tens digit (2) to the tens column:

Next, multiply 5 by 7. This time, 5 x 7 = 35. But you also need to add the 2 that you carried over, which makes the result 37. Because 5 and 7 are the last numbers to multiply, you don’t have to carry, so write down the 37 — you find that 53 x 7 = 371:

When multiplying larger numbers, the idea is similar. For example, suppose you want to multiply 53 by 47. Be sure to align the stacked numbers by the ones place. (The first few steps — multiplying by the 7 in 47 — are the same, so pick up the next step.) Now you’re ready to multiply by the 4 in 47. But remember that this 4 is in the tens column, so it really means 40. So to begin, put a 0 directly under the 1 in 371:

This 0 acts as a placeholder so that this row is aligned properly.

When multiplying by larger numbers with two digits or more, use one placeholding zero when multiplying by the tens digit, two placeholding zeros when multiplying by the hundreds digit

7 0
2 years ago
PLEASE HELP ME!!! I NEED HELP WITH GEOMETRY QUESTION ASAP!! DESPRATLY
BartSMP [9]

Answer:

The answer to your question is:      y = -3x + 14

Step-by-step explanation:

Data

A (4, 2)

y = x/3  - 1

Perpendicular

original slope = 1/3

perpendicular slope = -3

Equation                 (y - y1) = m(x - x1)

                               (y - 2) = -3(x - 4)

                               y - 2 = -3x + 12

                               y = -3x + 12 + 2

                               y = -3x + 14

4 0
4 years ago
If fx) 3x- 12, what is f2)?
bazaltina [42]

We are given function f(x) =3x-12

We have to find the value of f(2), that means we plug x as 2 in the given equation

f(2) = 3(2)-12

f(2) =6-12

f(2)=-6

Answer f(2)=-6

4 0
3 years ago
Please help me to solve this ∫ 1/(x + √x) dx
skad [1K]

Answer:

\boxed{2ln (\sqrt{x}  + 1 ) + c}

Step-by-step explanation:

\int\limits {\frac{1}{x + \sqrt{x} } } \, dx

= \int\limits {\frac{1}{\sqrt{x} (\sqrt{x}  + 1 )} } \, dx

= \int\limits {\frac{2}{(\sqrt{x}  + 1 )} } \, d(\sqrt{x}  + 1 )

= 2ln (\sqrt{x}  + 1 ) + c

6 0
3 years ago
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