Can you help me please

Identify the gas law that applies to the following scenario: A 36.5 liter balloon holding 2.9 moles of carbon dioxide leaks. If

Ksenya-84 [330]

Answer:

Avogadro's Law

Explanation:

The amount of moles is directly proportional to the volume of the gas under constant temperature and pressure. That is the statement of Avogadro's law. The equation is:

V1n2 = V2n1

<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas</em>

<em />

That means, right option is:

<h3>Avogadro's Law </h3>

6 0

3 years ago

Need help !!!!! ASAP

Nat2105 [25]

<h2>Hello!</h2>

The answer is:

The temperature will be the same, 37°C.

Since from the statemet we know the first temperature, pressure and volumen of a gas, and we need to calculate the new temperature after the pressure and the volume changed, we need to use the Combined Gas Law.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using Boyle's Law, Gay-Lussac's Law and Charles's Law.

The law establishes the following equation:

$\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}$

Where,

$P_{1}$ is the first pressure.

$V_{1}$ is the first volume.

$T_{1}$ is the first temperature.

$P_{2}$ is the second pressure.

$V_{2}$ is the second volume.

$T_{2}$ is the second temperature.

Then, we are given the following information:

$V_{1}=200mL\\P_{1}=4atm\\T_{1}=37\°C\\V_{2}=400mL\\P_{2}=2atm$

So, isolating the new temperature and substituting the given information, we have:

$\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\T_{2}=P_{2}V{2}*\frac{T_{1}}{P_{1}V_{1}} \\\\T_{2}=2atm*400mL*\frac{37\°C}{4atm*200mL}=37\°C$

Hence, we have that the temperature will not change because both pressure and volume decreased and increased proportionally, creating the same relationship that we had before the experiment started.

The temperature will be the same, 37°C

Have a nice day!

4 0

3 years ago

A sample of gas has a volume of 1.9L and a temperature of 21 degrees celsius. Heat is applied to the sample, leading to an incre

Mashutka [201]

Answer:

1.94 L

Explanation:

21°C = 21 +273 = 294 K

27°C = 27 + 273 = 300 K

T1/V1 = T2/V2

294 K/1.9 L = 300 K/x L

x = (1.9*300)/294 ≈ 1.94 L

3 0

4 years ago

1. What is the relationship between the concentration of the hydronium and hydroxide

Hitman42 [59]

Answer:

- Neutral solutions: concentration of hydronium equals the concentration of hydroxide.

- Acid solutions: concentration of hydronium is greater than the concentration of hydroxide.

- Basic solutions concentration of hydronium is lower than the concentration of hydroxide.

Explanation:

Hello,

It is widely known that the pH of water is 7, therefore the pOH of water is also 7 based on:

$pH+pOH=14$

In such a way, we can compute the concentration of hydronium and hydroxide ions as shown below:

$pH=-log([H^+])\\$

$[H^+]=10^{-pH}=10^{-7}=1x10^{-7}M$

$pOH=-log([OH^-])$

$[OH^-]=10^{-pOH}=10^{-7}=1x10^{-7}M$

Thus, we notice that the relationship between the concentration of the hydronium is equal for water or neutral solutions. Moreover, if we talk about acid solutions, pH<OH therefore the concentration of hydronium is greater than the concentration of hydroxide. On the other hand if we talk about basic solutions, pH>OH therefore the concentration of hydronium is lower than the concentration of hydroxide.

Best regards.

4 0

3 years ago

Write any three porperties of solid

Yanka [14]

Answer:

<em><u>A solid has a definite shape and volume.</u></em>

<em><u>A solid has a definite shape and volume.Solids in general have higher density.</u></em>

<em><u>A solid has a definite shape and volume.Solids in general have higher density.In solids, intermolecular forces are strong.</u></em>

<em><u>A solid has a definite shape and volume.Solids in general have higher density.In solids, intermolecular forces are strong.Solids have high melting points.</u></em>

7 0

3 years ago

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