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Fofino [41]
2 years ago
12

Identify the gas law that applies to the following scenario: A 36.5 liter balloon holding 2.9 moles of carbon dioxide leaks. If

we are able to determine that 1.2
moles of carbon dioxide escaped before the container could be sealed, what is the new volume of the container?
O Boyle's Law
Charles Law
Gay-Lussac's Law
Avogadro's Law

Chemistry
1 answer:
Ksenya-84 [330]2 years ago
6 0

Answer:

Avogadro's Law

Explanation:

The amount of moles is directly proportional to the volume of the gas under constant temperature and pressure. That is the statement of Avogadro's law. The equation is:

V1n2 = V2n1

<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas</em>

<em />

That means, right option is:

<h3>Avogadro's Law </h3>

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Washing soda, a compound used to prepare hard water for washing laundry, is a hydrate, which means that a certain number of wate
nadya68 [22]

Answer:

moles H₂O = 10

Explanation:

The mass of Na₂CO₃⋅xH₂O is 3.837 g and the mass of Na₂CO₃ is 1.42g

Therefore the mass of xH₂O is 3.837 - 1.42 = 2.417 g

The molar mass of Na₂CO₃ is 106 g/mol and for H₂O is 18 g/mol

The moles of Na₂CO₃ and H₂O in the sample are:

Na₂CO₃ = 1.42 / 106 = 0.01340 moles

H₂O = 2.417 / 18 = 0.1343

Now using rule of three :

1 mole of Na₂CO₃ has x moles of H₂O

0.01340 moles of Na₂CO₃ has 0.1343 moles of H₂O

x = 1 * 0.1343 / 0.01340 = 10

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3 years ago
What organelles are involved in the production of proteins
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endoplasmic reticulum (ER)

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2 years ago
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Which of the following is an acid?<br><br> Be(OH)2<br> HCl<br> LiBr<br> NH3
Lyrx [107]

Answer:

HCl is the correct answer

4 0
3 years ago
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Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
3 years ago
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