Answer:
ΔS° = -268.13 J/K
Explanation:
Let's consider the following balanced equation.
3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)
We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:
ΔS° = ∑np.Sp° - ∑nr.Sr°
where,
ni are the moles of reactants and products
Si are the standard molar entropies of reactants and products
ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]
ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]
ΔS° = -268.13 J/K
The smallest functional and structural unit of an organism, usually microscopic and consisting of cytoplasm and a nucleus in a membrane.
Answer:
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The electromagnetic force is responsible for most of the interaction we see in our environment today. The EMF holds electrons in their orbit around the nucleus.
Factors that can affect a magnets strength include : heat, radiation, strong, electrical currents in close proximity of to the magnet
The results of Rutherford's experiment were surprising as most of the alpha particles went straight without any deflection
<h3>Rutherford's Gold Foil experiment:</h3>
During the experiment, Rutherford directed beams of alpha particles at the thin gold foil and observed the following things:
- Most of the alpha particles passed straight without any deflection
- Few alpha particles got deflected from their paths on small angles
- Very few alpha particles got deflected from their paths on very large angles
<h3>Results of the experiment:</h3>
- Most of the space inside an atom is empty
- The center of the atom is occupied by a tiny positively charged dense body called a nucleus. Most of the mass of the atom is concentrated in the nucleus
- The electrons revolve around the nucleus in circular orbits and are called planetary electrons
Thus, the results of the experiment were surprising due to the above-stated facts.
Learn more about Rutherford's Gold Foil experiment:
brainly.com/question/4113533
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