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3 years ago

Name the property used in n + 0 = 7.

Mathematics

2 answers:

Naya [18.7K]3 years ago

8 0

Answer:

Step-by-step explanation:

Zero is the additive identity property.

Hope this helps

-Amelia

Svet_ta [14]3 years ago

8 0

Answer:

The property used in n+0=7 is additive identity property that is option ‘d’.

Solution:

Given that we have to find the property used in n + 0 = 7

The definition of additive identity property, is an identity element (such as 0 in the group of whole numbers under the operation of addition) that in a given mathematical system leaves unchanged any element to which it is added.

This perfectly satisfies our equation n+0=7.

Hence our the correct answer is additive identity property that is option ‘d’.

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for two positive integers a and b, we know g c d (a comma b )equals 15 comma space l c m (a comma b )equals 90, what is a b?

Scilla [17]

Two positive integers have gcd (a, b) = 15 and lcm (a, b) = 90. Those two numbers are 15 and 90 or 30 and 45.

Suppose we have 2 positive integers, a and b, then:

gcd (a, b) = the greatest common divisor = common prime factors of a and b

lcm (a, b) = the least common multiple = multiplication of the greatest common prime factors of a and b

In the given problem:

gcd (a, b) = 15

prime factorization of 15:

15 = 3 x 5

Hence,

a = 3 x 5 x ....

b = 3 x 5 x ....

lcm (a, b) = 90

prime factorization of 90:

90 = 3 x 5 x 2 x 3

Therefore the possible pairs of a and b are:

Combination 1:

a = 3 x 5 = 15

b = 3 x 5 x 2 x 3 = 90

Combination 2:

a = 3 x 5 x 2 = 30

b = 3 x 5 x 3 = 35

We can conclude the two integers are 15 and 90 or 30 and 45.

Learn more about gcd here:

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6 0

2 years ago

How do I solve x+2/3=5/6

aleksley [76]

You would subtract 2/3 from 5/6 and that should give you 1/6
x=1/6

4 0

3 years ago

Read 2 more answers

Savannah sets her watch 10.03 seconds behind and it falls behind another 1.09 seconds everyday. How many days has it been since

Pani-rosa [81]

Answer:

1 and 1/2 days

Step-by-step explanation:

ITHINK ITS HELP GOOD LUCK

8 0

3 years ago

Read 2 more answers

Hello! I'm having a really hard time solving this by Elimination and could really use some help

Mamont248 [21]

Answer:

x= 3, y=0, z= 1

Step-by-step explanation:

Let's label the 3 given equations first.

2x +3y +4z= 10 -----(1)

3x +2y -4z= 5 -----(2)

x +4y +2z= 5 -----(3)

(1) +(2):

This is to eliminate the z term.

2x +3y +4z +3x +2y -4z= 10 +5

5x +5y= 15

Divide by 5 on both sides:

x +y= 3 -----(4)

(3) ×2:

2x +8y +4z= 10 -----(5)

(2) +(5):

This is to eliminate z term.

3x +2y -4z + 2x +8y +4z= 5 +10

5x +10y= 15

Divide by 5 throughout.

x +2y= 3 -----(6)

(6) -(4):

x +2y -(x +y)= 3 -3

x +2y -x -y= 0

y= 0

subst. y=0 into (4):

x +0= 3

x= 3

subst. x=3, y=0 into (3):

3 +4(0) +2z= 5

3 +2z= 5

2z= 5 -3

2z= 2

z= 2÷2

z= 1

6 0

3 years ago

Question 5 (2 points)

Digiron [165]

1600 bc if you use your calculator that’s what you get

6 0

3 years ago