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emmasim [6.3K]
3 years ago
8

When buying a new dress, you have a choice of 3 different lengths, 5 different colors, and 2 different styles. How many choices

are there for one dress?
Mathematics
2 answers:
marshall27 [118]3 years ago
7 0
It is three because there is one of everything
Lana71 [14]3 years ago
3 0

Answer with explanation:

Number of choices in Length for a dress  = 3

Number of choices in Color for a dress= 5

Number of choices in Style for a dress= 2

To select a length out of 3 length ,which can be done in  _{1}^{3}\textrm{C}

To Select a color, among 5 different colors , can be done in  _{1}^{5}\textrm{C}.

To Select a Style, among 2 different styles , can be done in  _{1}^{2}\textrm{C}.

Total Number of ways

       =_{1}^{5}\textrm{C}\times_{1}^{3}\textrm{C}\times_{1}^{2}\textrm{C}\\\\= 5 \times 3 \times 2\\\\=30

                             

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<h3>Answer: </h3>

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The polynomial factors to 4(3x^2+x+5)

==========================================================

Further explanation:

Ignore the x terms

We're looking for the GCF of 12, 4 and 20

Factor each to their prime factorization. It might help to do a factor tree, but this is optional.

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Each factorization involves "2*2", which means 2*2 = 4 is the GCF here.

We can then factor like so

12x^2 + 4x + 20\\\\4*3x^2 + 4*x + 4*5\\\\4(3x^2 + x + 5)

The distributive property pulls out that common 4. We can verify this by distributing the 4 back in, so we get the original expression back again.

The polynomial inside the parenthesis cannot be factored further. Proof of this can be found by looking at the roots and noticing that they aren't rational numbers (use the quadratic formula).

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