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lapo4ka [179]
3 years ago
14

Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because they carry enough energy to b

reak bonds within the molecules. A carbon-sulfur bond requires 272 kJ/mol to break. What is the longest wavelength of radiation with enough energy to break carbon-sulfur bonds
Chemistry
1 answer:
Alja [10]3 years ago
4 0

Answer:

439.7nm

Explanation:

Energy of a quantum can be calculated using below formula

E=hv...........eqn(1)

But v=λ/ c .........eqn(2)

If we substitute eqn(2) into eqn(1) we have

E= hc/(λ)

Where E= energy

h= Plank's constant= 6.62607004 × 10-34 m2 kg / s

c= speed of light

c= 2.998 × 10^8 m/s

λ= wavelength= ?

But the energy was given in Kj , it must be converted to Kj/ photon for unit consistency.

Energy E= 272 kJ/mol × 1mol/6.02× 10^23

Energy= 451.83× 10^-24 Kj/ photon

E= hc/(λ)...........eqn(1)

If we make λ subject of the formula

λ= hc/E

Then substitute the values we have

λ= [(6.626 × 10^-34) × (2.998 × 10^8)]/451.83× 10^-24

λ=(0.00043965) × (1Kj/1000J) × (10^9nm/1m)

λ=439.7nm

Hence, the longest wavelength of radiation with enough energy to break carbon-sulfur bonds is 439.7nm

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C) the energy transferred between objects t different temperatures

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Answer:

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5 0
3 years ago
Read 2 more answers
Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.
vlada-n [284]

Answer:

2.03

Explanation:

Let's <u>assume we have 1 L of the solution</u>:

  • There would be 2.07 ethylene glycol moles.
  • The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.

With that information we can <u>calculate the molality</u>:

  • molality = moles of solute / kg of solvent
  • molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

3 0
3 years ago
Given the following reaction: H2SO4+2LiOH=Li2SO4+2H20, what mass of water is produced from 19 g of sulfuric acid?
goldfiish [28.3K]

Hi,

To solve the question, first of all we will find out the no. of moles of H2SO4 in  19 g of sulfuric acid.

As we know:

              No . of moles = Mass/ Molar mass

              No. of moles= 19 g/98.08 g

               No. of moles= 0.1937

Now we know the no of moles of H2SO4 that will react with 2LiOH. We also know the  molar equivalence of H2SO4 , and 2LiOH that will react.

So, the  water that will be produced will be 2H2O and 1 Li2SO4 when H2SO4 that will react with 2LiOH.

                          0.1937 x 2x 18.01

                                 =6.977

                                  =6.98

Therefore, approximately 6.98 grams of water will be produced from 19 g of sulfuric acid.


Hope it helps!


5 0
3 years ago
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