The % V/V concentration of a 180-mL disinfectant solution containing 85 mL of isopropyl alcohol is 47 % V/V.
<h3>What is the % V/V concentration?</h3>
It refers to the milliliters of solute for every 100 milliliters of solution.
We have 180 mL of a disinfectant solution that contains 85 mL of isopropyl alcohol (solute).
The % V/V concentration of this solution is:
% V/V = (mL solute/mL solution) × 100% =
% V/V = (85 mL/180 mL) × 100% = 47% V/V
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<span>The root mean square speed is given by V_rms = âšRT/M where r, t, and m are the rate constant, temperature and molar mass the gas
Average molar kinetic energy of the gas
E = 1/2 M * (V_rms)^2 = 8750 ms/1
So (V_rms)^2 = (2 * 8750) / M
Molar mass of 2 chlorine atoms in kg is 2 * 35 * 10^(-3)
Hence we have (V_rms)^2 = (2 * 8750)/ (2 * 35 * 10^(-3))
(V_rms)^2 = 8750/0.035 = 250000
So V_rms = âš 250000 = 500</span>
The grams of ethane present in a sample containing 0.4271 mole is 12.84 g
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the mass of ethane. Details below
<h3>How to determine the mass of ethane</h3>
The following data were obtained from the question:
- Mole of ethane = 0.4271 mole
- Molar mass of ethane = 30.067 g/mol
- Mass of ethane =?
The mass of ethane present in the sample can be obtained as follow:
Mole = mass / molar mass
Cross multiply
Mass = mole × molar mass
Mass of ethane = 0.4271 × 30.067
Mass of ethane = 12.84 g
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A good example is cigarretes they try to scare you into not smoking by telling you all of the downsides of smoking like lung cancer and i guess that would be fear appeal
