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devlian [24]
3 years ago
14

Why do you think the experimenter conducted this experiment in a lab rather than in the natural world, where this

Chemistry
1 answer:
yan [13]3 years ago
6 0

Answer: The experimenter conducted this experiment in allowed to control the conditions and limit the number of variables

Explanation:

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If 10.0g of oxygen reacts with 10.0g of hydrogen, how many grams of water can be
rusak2 [61]

Answer:

the answer is 90g

Explanation:

2g of H2 produce 18g of H2O/10.0g of H2 to produce x the answer is 90g

8 0
3 years ago
In a ________ change, such as a change of state, the substance as a whole changes, but its underlying structure remain the same.
pav-90 [236]

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Im pretty sure it is chemical change

4 0
3 years ago
A manganese electrode was oxidized electrically. If the mass of the electrode decreased by 225 mg during the passage of 1580 cou
qwelly [4]

Answer:

<u>Oxidation state of Mn = +4</u>

Explanation:

Atomic mass of Mn = 55g/mol

From Faraday's law of electrolysis,

Electrochemical equivalent = \frac{mass}{charge}

i.e Z = \frac{m}{Q} = \frac{0.225g}{1580C} = 0.0001424 g/C

But Equivalent weight, E = atomic mass ÷ valency  = Z × 96,485

⇒ \frac{55}{valency} = 0.0001424 × 96,485

<u>∴ Valency of Mn = +4</u>

8 0
3 years ago
Comparing Mirrors
mote1985 [20]

Answer:

convex

convex

concave

plane

Explanation:

4 0
4 years ago
Read 2 more answers
The question is below
rodikova [14]
The anode is the electrode where the oxidation occurs.

Cathode is the electrode where the reducction occurs.

Equations:

  Mn(2+) + 2e-  --->  Mn(s)                      Eo = - 1.18 V
2Fe(3+) + 2e-  ----> 2 Fe(2+)                2Eo = + 1.54 V

The electrons flow from the electrode with the lower Eo to the electrode with the higher Eo yielding to a positive voltage.

Eo = 1.54 V - (- 1.18) = 1.54 + 1.18 = 2.72

Answer: 2.72 V

3 0
3 years ago
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