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devlian [24]
2 years ago
14

Why do you think the experimenter conducted this experiment in a lab rather than in the natural world, where this

Chemistry
1 answer:
yan [13]2 years ago
6 0

Answer: The experimenter conducted this experiment in allowed to control the conditions and limit the number of variables

Explanation:

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An iron object alloyed with cobalt rusts more quickly than a pure iron object. However, an iron object alloyed with manganese ru
HACTEHA [7]

Rusting is an electrochemical reaction. Iron rusts faster when alloyed with cobalt than when alloyed with manganese because, in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode

An alloy is a combination of two metals. There are various reasons for producing alloys such as greater tensile strength, corrosion resistance and improved aesthetic appearance.

When iron is alloyed with cobalt, the iron rusts faster than pure iron because iron is rendered the anode and cobalt is rendered the cathode. When the iron is alloyed with manganese, it rusts more slowly than pure iron because in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode.

Missing parts;

An iron object alloyed with cobalt rusts more quickly than a pure iron object. However, an iron object alloyed with manganese rusts less quickly than a pure iron object under the same conditions. This is true because

(1) cobalt is a stronger reducing agent than iron

(2) iron is a stronger reducing agent than manganese

(3) cobalt exhibits more metallic character than either iron or manganese

(4) in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode

(5) in the iron-cobalt alloy, cobalt is rendered the anode and iron is rendered the cathode

Learn more: brainly.com/question/14281129

5 0
2 years ago
[1] b) In a local election there were 8000 registered voters. Of these 3200 voted. What was the percentage that voted? [1] <​
Alexandra [31]

Answer:

40% of registered voters voted

Explanation:

3200 out of 8000,

or :

3200 / 8000

= 0.4

0.4 x 100 = 40

40% of registered voters voted

4 0
2 years ago
How many atoms are there in 10.2 moles of Phosphorous?​
nikdorinn [45]

There are 2.06 x 10²⁴ atoms

<h3>Further explanation </h3>

The mole is the number of particles (atoms, molecules, ions)contained in a substance

1 mol = 6.02.10²³  particles

Moles can also be determined from the amount of substance mass and its molar mass

  • number of atoms :

\tt 10.2\times 6.02\times 106{23}=2.06\times 10^{24}

5 0
3 years ago
What would be the formula of the compound iron (III) phosphide?
irina1246 [14]
<span>Fe3P 
hope it help's you 


</span>
7 0
3 years ago
Read 2 more answers
Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas
hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Suppose 1.20 mol CS_2(g) of and 3.60 mol of Cl_2(g)  were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol  of CCl_4. Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of  CS_2 = 1.20 mole

Moles of  Cl_2 = 3.60 mole

Volume of solution = 1.00  L

Initial concentration of CS_2 = \frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M

Initial concentration of Cl_2 = \frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M

The given balanced equilibrium reaction is,

                 CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Initial conc.         1.20 M        3.60 M                  0                  0

At eqm. conc.     (1.20-x) M   (3.60-3x) M   (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}

Now put all the given values in this expression, we get :

K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}

Given :Equilibrium concentration of CCl_4 , x = \frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M

K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}

K_c=0.36

Thus equilibrium constant at unknown temperature is 0.36

4 0
2 years ago
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