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4 years ago

Marlin Davies buys a truck for $28,000 in three years the truck depreciates 48% in value how much is the truck worth in 3 years

Mathematics

2 answers:

marysya [2.9K]4 years ago

6 0

Answer: $ 14560

Step-by-step explanation:

Here, The initial price of truck = $ 28,000

According to the question,

In three years the truck depreciates 48% in value.

Thus, the truck worth in three year = (100-48)% of 28,000

= 52% of 28,000

= $\frac{28000\times 52}{100}$

= $\frac{1456000}{100}$

= $14560$

⇒ the truck worth in three year = $ 14560

serious [3.7K]4 years ago

3 0

28,000 × 0.48 = 13,440
and
28,000
- 13,440
---------------
$14,560 is the current value of the truck

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ratelena [41]

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By definition

$tanh \ x=\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}}$

Then,

$\frac{1-tanh \ x}{1 + tanh \ x}=\frac{1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }{1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

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2 years ago

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Svetlanka [38]

Answer:

99% confidence interval is:

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Step-by-step explanation:

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$[(p_{1} - p_{2}) \pm z_{\alpha/2} \sqrt{\frac{p_{1}(1-p_{1})}{n_{1}} + \frac{p_{2}(1-p_{2})}{n_{2}} }$

Where $p_{1}$ : proportion sample of individuals who worked

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