Answer:
55 ° is correct answer option (c)
Answer:
Step-by-step explanation:
From the problem statement, we can create the following equation:
where 
is the age of James, 
is the age of Paul, and 
is the age of Dan.
From the first part of the second sentence, we can set up the following equation:
From the last part of the second sentence, we can set up the following equation:
We can substitute the second equation into the last one to get the following:
We can then substitute the last two equations in the first to solve for :
Plugging this into the other two equations will give us the remaining ages:
Answer:
The Principal = $75,000
Step-by-step explanation:
Formula for finding the principal:
I × 100/ R × T
Therefore;
Principal = 45 × 100 / 3/ 100 × 2
Which means that the Principal is $75,000.00
<span>Alex wants to borrow $1,000. The local bank says "10% Interest". So to borrow the $1,000 for 1 year will cost:$1,000 × 10% = $100</span>
In this case the "Interest" is $100, and the "Interest Rate" is 10% (but people often say "10% Interest" without saying "Rate")
Of course, Alex will have to pay back the original $1,000 after one year, so this is what happens:
Alex Borrows $1,000, but has to pay back $1,100<span>This is the idea of Interest ... paying for the use of the money</span>
Answer:
5 sets
Step-by-step explanation:
The average number of pieces per set is the ratio of the total number of pieces to the total number of sets.
Let x represent the number of 3-piece sets. Then the total number of pieces is ...
3x +5(5) +10(2) = 3x +45
The total number of sets is ...
x +5 +2 = x +7
We want the ratio of these numbers to be 5 pieces per set:
(3x +45)/(x +7) = 5
3x +45 = 5x +35 . . . . . multiply by (x+7)
10 = 2x . . . . . . . . . . subtract (3x+35)
5 = x . . . . . . . . . divide by 2
Divya owns 5 sets with 3 pieces.
_____
<em>Alternate solution</em>
Each 10-piece set has 5 more pieces than average, so the two of them total 10 more pieces than average.
Each 3-piece set has 2 fewer pieces than average. The total number of 3-piece sets must have a total of 10 fewer pieces than average in order to balance the excess of the 10-piece sets. That is, there must be 10/2 = 5 of the 3-piece sets to have a total lof 10 fewer pieces than average.
Altogether, the differences from average must total zero.
