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3 years ago

Given the equation:

Chemistry

2 answers:

notsponge [240]3 years ago

4 0

Answer: The correct answer is Option 2.

Explanation:

For the given options:

Option 1: Hydroxide ion

The chemical formula for this ion is $OH^-$

Option 2: Hydronium ion

The chemical formula for this ion is $H_3O^+$

Option 3: Hypochlorite ion

The chemical formula for this ion is $ClO^-$

Option 4: Perchlorate ion

The chemical formula for this ion is $ClO_4^-$

For the given chemical reaction:

$HCl(g)+H_2O(l)\rightarrow H_3O^+(aq.)+Cl-(aq.)$

The ion represented by X is hydronium ion.

Hence, the correct answer is Option 2.

Archy [21]3 years ago

3 0

X will be hydronium (H3O)

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Saltwater _____. has a pH of 10 is mostly used for irrigation and farming can be desalinized and used for drinking is mostly fou

tiny-mole [99]

I think the best statement to fill the blank is that "can be desalinized and used for drinking". The said statement seems the most appropriate one because the pH of saltwater is not 10 but approximately between 7.6 to 8.4. Also, saltwater is not found in glaciers, ice caps and aquifers instead it is freshwater.

8 0

3 years ago

Consider this reaction involving an unknown element X. F2+2XBr⟶Br2+2XF When 1.300 g of XBr reacts, 0.7241 g of Br2 is produced.

scZoUnD [109]

The molar mass of X would be 63.55 g/mol and the chemical symbol of X would be Cu (copper).

From the equation of the reaction: F2+2XBr⟶Br2+2XF

The mole ratio of XBr to Br2 is 2:1

Mole of Br2 = mass/molar mass

= 0.7241/159.808

= 0.004531 mole

Mole of XBr = 2 x mole of Br2

= 2 x 0.004531

= 0.009062 mole

Molar mass of XBr = mass/mole

= 1.300/0.009062

= 143.456 g/mol

Since the molar mass of Br is 79.904, the molar of X would be:

143.456 - 79.904

= 63.55 g/mol

Hence, X would be Cu.

More on molar mass calculation can be found here: brainly.com/question/20691135

6 0

2 years ago

Chemical reactions can be detected by changes in:

Molodets [167]

Chemical reactions can be detected by changes in temperature

7 0

3 years ago

A student chromatographs a mixture and after developing the spots with a suitable reagent he observes the following

Anika [276]

Rf value is the ratio of the distance traveled by the solute to that of the solvent front on the paper used in chromatographic separation.

From the image it is clear the distance traveled by solvent front = 7.3 cm

Distance traveled by the component -1 of the mixture = 1.4 cm

Distance traveled by the component -2 of the mixture = 3.0 cm

Distance traveled by the component -3 of the mixture = 4.5 cm

Distance traveled by the component -4 of the mixture = 6.5 cm

Rf value of component-1 = $\frac{1.4 cm}{7.3 cm} =0.192$

Rf value of component-2 = $\frac{3.0 cm}{7.3 cm} =0.410$

Rf value of component-3 = $\frac{4.5 cm}{7.3 cm} =0.616$

Rf value of component-4 = $\frac{6.5 cm}{7.3 cm} =0.890$

b) Samples can be separated from a mixture using chromatography as the relative affinities for the compounds towards the paper (stationary phase) and the solvent(mobile phase) are different. Each component spends different amounts of time on the stationary phase depending on it chemical nature. So, the components in a mixture can be separated based on their polarities and relative degrees of adsorption on the stationary phase.

6 0

3 years ago

Fe(II) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fe(II)

vovangra [49]

Answer:

0,051g of O₂

Explanation:

The reaction of precipitation of Fe is:

4Fe(OH)⁺(aq) + 4OH⁻(aq) + O₂(g) + 2H₂O(l) → 4Fe(OH)₃(s)

-Where the Fe(OH)⁺ is Fe(II) and Fe(OH)₃ is Fe(III)-

This reaction is showing you need 1 mol of O₂(g) per 4 moles of Fe(II) for a complete reaction.

85mL= 0,085L of 0,075M Fe(II) are:

0,085L*0,075M = 6,34x10⁻³ moles of Fe(II)

For a complete reaction of 6,34x10⁻³ moles of Fe(II) you need:

6,34x10⁻³ moles of Fe(II)× $\frac{1molO_2}{4moles Fe(II)}$ =

1.59x10⁻³ moles of O₂. In grams:

1.59x10⁻³ moles of O₂× $\frac{32g}{1molO_2}$ = 0,051g of O₂

I hope it helps!

7 0

2 years ago