What is the maximum mass of ethyl alcohol you could boil with 2000 JJ of heat, starting from 17 ∘C∘C?
2 answers:
Answer:
maximum mass C2H5OH = 13.398 g
Explanation:
∴ Q = 2000 J
∴ Cp C2H5OH = 112.0 J/mol.K
∴ T1 = 17°C = 290 K
∴ T2 = Tboil C2H5OH = 78.4°C = 351.4 K
⇒ ΔT = 351.4 K - 290 K = 61.4 K
∴ m = Q/CpΔT
⇒ mol C2H5OH = (2000 J)/((112.0 J/mol.K)(61.4 K)) = 0.29083 mol
∴ mm C2H5OH = 46.07 g/mol
⇒ mass C2H5OH = (0.29083 mol)×(46.07 g/mol) = 13.398 g
Answer: Q=mcΔT
Explanation:
c ethyl alcohol = 2400 J/(kg*K)
T boil ethyl alcohol = 78 C = 351 K
T starting = 17 C = 290 K
m=Q/(c*ΔT)
m= (2400 J)/[(2400 J/kg*K)(351 K -290 K)]
= 0.0028g
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