Group 18 is known as the Noble/ Inert Gases
Answer:
Δ S = 26.2 J/K
Explanation:
The change in entropy can be calculated from the formula -
Δ S = m Cp ln ( T₂ / T₁ )
Where ,
Δ S = change in entropy
m = mass = 2.00 kg
Cp =specific heat of lead is 130 J / (kg ∙ K) .
T₂ = final temperature 10.0°C + 273 = 283 K
T₁ = initial temperature , 40.0°C + 273 = 313 K
Applying the above formula ,
The change in entropy is calculated as ,
ΔS = m Cp ln ( T₂ / T₁ ) = (2.00 )( 130 ) ln( 283 K / 313 K )
ΔS = 26.2 J/K
X is dependent Y is independent.... number of students is Y flavor is X
Answer: The final pressure is 34.48kPa
Initial Pressure P1 = 55.16kPa
Initial Volume V1 = 0.500L
Final Pressure P2 = ?
Final Volume V2 = 0.800L
Boyle's law P1V1 = P2 V2
P2 = P1V1/V2
P2 = 55.16*0.5/0.8
P2 = 34.48kPa
Answer:

Explanation:
Hello,
In this case, for latent heat (phase change) we need to consider the enthalpy associated with the involved process, here, melting or fusion; thus, the enthalpy of fusion of copper is 13.2 kJ/mol, therefore, the heat is computed as:

Nevertheless, since the given enthalpy is per mole of copper, we need to use its atomic mass to perform the correct calculation as follows:

Which is positive as it needs to be supplied to the system.
Best regards.