<h3>
Answer:</h3>
56.11 g/mol
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Compound] KOH
<u>Step 2: Identify</u>
[PT] Molar Mass of K - 39.10 g/mol
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mass of H - 1.01 g/mol
<u>Step 3: Find</u>
39.10 + 16.00 + 1.01 = 56.11 g/mol
By definitions of the prefixes in the metric system, the prefix milli- (abbreviated as m as in mg) indicates 1/1000 or 1 x 10^-3 of a gram. In this case, if a beaker has a mass of 77.275 g (I am assuming this is grams since most other units would make it too heavy or too light), we would multiply this by 1000 to convert it to milligrams. So 77.275 g = 77,275 mg.
The correct answer is: THEY ARE SOLD AS CASH CROPS.
