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Fed [463]
3 years ago
10

Simplify (x^5)^5 i cant get it

Mathematics
2 answers:
ra1l [238]3 years ago
6 0

Answer:

Pretty sure the answer is x^25

olga2289 [7]3 years ago
4 0
Apply the power rule and multiply exponents,
(
a
m
)
n
=
a
m
n
(
a
m
)
n
=
a
m
n
.
x
5
⋅
5
x
5
⋅
5
Multiply
5
5
by
5
5
.
x
25
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When written in standard form, the product of (3+x) and (2x-5)
Mariulka [41]

Answer:

2x^2+x-15

Step-by-step explanation:

6x-15+2x^2-5x

2x^2+x-15

5 0
3 years ago
An amusement park charges $5 for admission and $.80 for each ride. You go to the park with $13. Which inequality represents this
RSB [31]

Answer:

Answer Placeholder (I'm going to solve it and answer when I'm done)

Step-by-step explanation:

7 0
3 years ago
A company charges $7 for a T-shirt and ships any order for $22. A school principal ordered a number of T-shirts for the school s
Harlamova29_29 [7]

Answer: The awnser would be D

5 0
3 years ago
Help!!!!!! Quick <br> Evaluate (x + y)° for x = -3 and y = 5.<br> - 1/2<br> 2<br> 1<br> O
MrMuchimi

Answer:

it is 1

Step-by-step explanation:

The power of 0 causes all numbers to negate to 1.
Anything to the power of 0 is 1


For example:

(10)^0 = 1

7 0
2 years ago
Geometry
Kobotan [32]

Answer: UV = 52

Concept:

Additive property of length, or the segment addition postulate, states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Solve:

<u>Given information</u>

TU = 4x

UV = 2x + 14

TV = 7x - 5

<u>Given expression deducted from the additive property of length</u>

TV = TU + UV

<u>Substitute values into the expression</u>

7x - 5 = 4x + 2x + 14

<u>Combine like terms</u>

7x - 5 = 6x + 14

<u />

<u>Subtract 6x on both sides</u>

7x - 5 - 6x = 6x + 14 - 6x

x - 5 = 14

<u>Add 5 on both sides</u>

x - 5 + 5 = 14 + 5

x = 19

<u>Find UV by substituting the value of x</u>

UV = 2x + 14 = 2 (19) + 14 = \boxed{52}

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
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