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olganol [36]
3 years ago
12

How do you solve the equation z-2z-3=-7

Mathematics
1 answer:
finlep [7]3 years ago
4 0
Hey, it’s very easy. You just need to do like that:

z-2z-3=-7
z-2z= -7+3
-1z = -4 | : (-1)
z = 4

The answer is 4.
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The length,AB of the rectangular lot is 1 foot less than two times its width, BC. If the perimeter of the rectangular lot 394 fe
r-ruslan [8.4K]

Answer:

AB=131\ ft

Step-by-step explanation:

we know that

The perimeter of the rectangular lot is

P=2(AB+BC) ----> equation A

where

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6 0
3 years ago
when directed to solve a quadratic equation by completing the square, Sam arrived at the equation (x-(5/2))^2= (13/4). which equ
Tasya [4]
We have the following expression:
 (x- (5/2)) ^ 2 = (13/4)
 Let's rewrite the given expression:
 x ^ 2 - 5x + 25/4 = (13/4)
 x ^ 2 - 5x + 25/4 - 13/4 = 0
 x ^ 2 - 5x + 12/4 = 0
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 Answer:
 
the original equation given to Sam could have been:
 
x ^ 2 - 5x + 3 = 0
7 0
2 years ago
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