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Karolina [17]
3 years ago
10

What is the solution to the equation?

Mathematics
1 answer:
Elza [17]3 years ago
6 0
5x+10=-4x-17 \\
5x+4x=-17-10 \\
9x=-27 \\
x=\frac{-27}{9} \\
\boxed{x=-3} \Leftarrow \hbox{answer C}
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Four times a number would equal 4n
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Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and
Brums [2.3K]

Answer:

t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349      

p_v =P(t_9>10.349)=1.34x10^{-6}  

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

Step-by-step explanation:

1) Data given and notation      

\bar X=51.6 represent the sample mean

s=1.1 represent the standard deviation for the sample      

n=10 sample size      

\mu_o =48 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean score is higher than 48, the system of hypothesis would be:      

Null hypothesis:\mu \geq 48      

Alternative hypothesis:\mu > 48      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349      

Calculate the P-value      

First we find the degrees of freedom:

df=n-1=10-1=9

Since is a one-side upper test the p value would be:      

p_v =P(t_9>10.349)=1.34x10^{-6}  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.        

5 0
3 years ago
Use the grouping method to factor x³ + x² + 3x+3.
Annette [7]

Answer:

D. (x + 1)(x^2 + 3)

Step-by-step explanation:

Hello!

We can group the first two terms and the last two terms.

<h3>Factor by Grouping</h3>
  • x^2 + x^2 + 3x + 3
  • x^2(x + 1) + 3(x + 1)
  • (x^2 + 3)(x + 1)

Factoring by grouping is the process of breaking down larger polynomials to smaller ones to factor. We can then combine like factors.

In the second step, we can see that we can rewrite x^3 + x^2 as x^2(x + 1), as both the two terms share a common factor of x^2. We can pull out x^2 from that expression. Similarly, 3x and 3 share a common factor of 3, so we can pull that out.

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PLEASE PLEASE HELP
marta [7]

Answer:

Approximately 3 grams left.

Step-by-step explanation:

We will utilize the standard form of an exponential function, given by:

f(t)=a(r)^t

In the case of half-life, our rate <em>r</em> will be 1/2. This is because 1/2 or 50% will be left after <em>t </em>half-lives.

Our initial amount <em>a </em>is 185 grams.

So, by substitution, we have:

\displaystyle f(t)=185\big(\frac{1}{2}\big)^t

Where <em>f(t)</em> denotes the amount of grams left after <em>t</em> half-lives.

We want to find the amount left after 6 half-lives. Therefore, <em>t </em>= 6. Then using our function, we acquire:

\displaystyle f(6)=185\big(\frac{1}{2}\big)^6

Evaluate:

\displaystyle f(6)=185\big(\frac{1}{64}\big)\approx2.89\approx 3

So, after six half-lives, there will be approximately 3 grams left.

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3 years ago
Find the 4th term (x-y)^12
maria [59]

Answer:

The fourth term of the expansion is -220 * x^9 * y^3

Step-by-step explanation:

Question:

Find the fourth term in (x-y)^12

Solution:

Notation: "n choose k", or combination of k objects from n objects,

C(n,k) = n! / ( k! (n-k)! )

For example, C(12,4) = 12! / (4! 8!) = 495

Using the binomial expansion formula

(a+b)^n

= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n

For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is

C(n,3)a^(n-3)b^3

=C(12,3) * x^(12-3) * (-y)^(3)

= 220*x^9*(-y)^3

= -220 * x^9 * y^3

3 0
3 years ago
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