If all the angle formed by line segments QA and AB has the same degree as the angle formed by line segments AB and BP, and line the following sets of line segments have the same length, then they are congruent triangles.
AP and QB
AQ and BP
Hope this helped.
Answer:
no solutions.
Step-by-step explanation:
8x + 14 -4x = 9+4x -5
8x-4x -4x = 9-5-14
0x = -10
anything multiplied by 0 is 0, so it's impossible to get -10 by multiplying by 0
4+2.2h=-3.7
2.2h=-7.7
h=-7.7/2.2=-7/2=-3.5
The answer is -3.5
Good luck!
I think it would be "It has 2 terms and a degree of 2", because the 3x^2y^2 and the -3x^2y^2 cancel out. Then, you're left with -5xy^2+2x^2.
In what remains, there are 2 terms, each with the highest degree of 2, so I would be led to believe A is your answer.
