Question

Pls help me do this (atleast one) using quadratic formula​

Answer 1

⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✿⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎

Hi my lil bunny!

❀ _____.______❀_______._____ ❀

Let's solve your equation step-by-step.

$\frac{x - 1}{x + 1} + \frac{x + 3}{ x - 3} = \frac{2( x+2)}{x - 2}$

$\frac{x - 1}{ x + 1} + \frac{x + 3}{ x - 3} = \frac{2x + 4}{x - 2}$

Multiply all terms by (x+1)(x-3)(x-2) and cancel:

$( x- 1 ) ( x - 3 ) (x - 2 ) + ( x + 3) ( x +1 ) ( x - 3) = ( 2x + 4) ( x + 1) ( x - 3)$

$2x^3 - 4x^2 + 6x - 12 = 2x^3 - 14x - 12$ (Simplify both sides of the equation)

$2x^3 - 4x^2 + 6x - 12 - 2x^3 = 2x^3 - 14x - 12 ( - 14x - 12)$ (Subtract 2x^3 from both sides)

$-4x^2 + 6x - 12 = -14x -12\\-4x^2 + 6x - 12 - ( -14x - 12) = -14x -12 - (-14x - 12)$

                         ↑

(Subtract -14x-12 from both sides)

$-4x^2 + 20x = 0\\4x( -x +5) =0$   (Factor left side of equation)

$4x = 0 or -x + 5 = 0$ (Set factors equal to 0)

$x = 0 or x = 5$

Check answers. (Plug them in to make sure they work.)

$x = 0$ (Works in original equation)

$x = 5$ (Works in original equation)

So the answer is $= x = 0 or x = 5$

❀ _____.______❀_______._____ ❀

Xoxo, , May

⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✿⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎

Hope this helped you.

Could you maybe give brainliest..?

Answer 2

hey ....

Here are your answers in the given attachment. Please let me know if there's any error.