In eukaryotes, there are two distinct types of cell division: a vegetative division, whereby each daughter cell is genetically identical to the parent cell (mitosis), and a reproductive cell division, whereby the number of chromosomes in the daughter cells is reduced by half to produce haploid gametes (meiosis).
The light-independent reactions, or dark reactions, of photosynthesis are chemical reactions that convert carbon dioxide and other compounds into glucose.
Answer:
The answer is A. There is more genetic variation in organisms that reproduce sexually than those that reproduce asexually.
Explanation:
This is because offspring with two parents can get genetics from both family's which means there is a chance for many different types of characteristics.
If an offspring only has one parent however, the offspring will only get those genetics from the parent which means there are not many possibilities for offspring to look or act different then their parent.
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Answer:
Prophase
Prometaphase
Metaphase
Anaphase
Cytokinesis and Telophase (Yes two answers)
Explanation:
Prophase is when the chromosomes condense
Prometaphase is when nuclear envelope dissolves
Metaphase, M for middle, meaning all chromosomes line up at middle
Anaphase, A for apart, meaning all chromosomes are taken apart in half
Telophase is the formation of 2 different nuclei, and Cytokinesis splits it
Answer:
Explanation:
The missing diagram contained in this question is first attached in the image below.
The objective of this question is to determine how ions migrate when the cells are operating by assuming the solutions are composed of Ni(NO3)2.
From the information provided:
In this instance, the ions tend to move first from cathode to anode in terms of raising the concentration of Ni(2+) at the anode, resulting in the development of a dead cell. The initial concentration of [Ni(2+)] in the anode solution is 1.00 × 10⁻³ M, which gradually increases to 0.5 M, during which both the cathode and the anode possess the same concentration at the same point.
This causes Q(equilibrium constant) to equal 1 as well as log(Q) to equal 0, indicating that the cell is dead.
As a result, the cell will cease to operate, and nothing will migrate from the left to the right side.
