Answer:
What is this off of, can you give me more information so I can help you
Explanation:
Answer:
B) Multicellular Simple gland
Explanation:
Exocrine Glands:Glands that secrete their products onto the apical(or epithelia) surface directly or via epithelial ducts or tubes that are connected to the apical surface. These Exocrine glands are composed of highly specialized epithelial cells..
Exocrine glands can either be branched or Unbranched based on the arrangement.
*Multicellular simple glands*:Glands that have an *unbranched duct* into which cells secrete. Each secretory portion empties separately on an epithelial surface.
Answer:
b) opening calcium pores in the membrane
Explanation:
The opening of calcium ions channels facilitates the migration of vesicles containing neurotransmitters in the pre-synaptic neurons to the tip of the post-synaptic membrane. at the <u>neuromuscular junction </u>These neurotransmitters can either be <u>cholinergic or non-chorlinergic.</u> <u>At the tip of the pre-synaptic membranes the vesicles empty their neurotransmitter contents into the synapse.</u>
The neurotransmitters, diffuse through the neuromuscular junction to bind with the receptors on the <u>post-synaptic membrane on the post-synaptic neuron.</u> This stimulates opening of<u> ligand gated sodium ions,</u> and sodium ions diffuse into the post-synaptic neuronal membrane, to cause <u>depolarization</u>. if the stimulus is up to the threshold levels it generate action potential.
Therefore , more calcium ions channels opening produces; more diffusion of neurotransmitters;leading to opening of more sodium channels for depolarization; and IPSP or EPSP generation.
Explanation:
The phenotypes and genotypes of the progeny can be determined by a dihybrid cross of the parents.
The heterozygous male will have the genotype 'SSww' and the heterozygous female will have the genotype 'ssWW'.
When crossed, the F1 offsprings will have a hybrid genotype of 'SsWw'. These offsprings are heterozygous with spotted skin and wooly hair.
On self-crossing of the F1 hybrids, we find four different combinations of the alleles- SW, Sw, SW and sw. The probability of getting each of these combinations is 1/4.
Hence, the probability of any dihybrid type is 1 out of the 16 possible genotypes. Using Punnet square, we find
9 SSWW: 3 SSww: 3 ssWW : 1 ssww
This is the phenotypic ratio of the offsprings.
The ratio of the possible genotypes will be 1:2:1:2:4:2:1:2:1.