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algol13
3 years ago
11

A(n) ____ is software that can be used to block access to certain Web sites that contain material deemed inappropriate or offens

ive.
Trojan horse
Virus
Internet filter
Worm
Computers and Technology
1 answer:
serious [3.7K]3 years ago
4 0

Answer: <em>Internet filter</em>

Explanation:

Internet filters are referred to as software which prevents individuals from accessing certain kind of websites. These filters are predominantly used in order to block content that might be considered inappropriate for some users. These filters are widely used in public library and computers used by schools and colleges.

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Answer:

Throughout the clarification segment below, the essence including its query is mentioned.

Explanation:

  • The analytical techniques utilize magnetic fields that allow the waves to be analyzed.
  • They sometimes use echolocation strategies.
  • It is possible to be using artificial intelligence to research potential forecasts. Climate, improvements throughout the climate as well as other things.
  • Like toxic waves, this will be capable of predicting tides.
5 0
2 years ago
How many questions do you have to answer before you can use direct messages on Brainly?
steposvetlana [31]

Answer:

im pretty sure it 5

Explanation:

4 0
3 years ago
Read 2 more answers
Analyze the following code:
olganol [36]

Answer:

The program displays 5 4 3 2 1 and then raises an Array Index Out Of Bounds Exception.

Explanation:

A sample of code output is attached.

The code snippet contain xMethod that takes an array and array length as argument.

In the given snippet, the array {1, 2, 3, 4, 5} and length (5) is passed as argument to the method.

First the method display the element of the array in reverse order

System.out.print(" " + x[length - 1]);

and then the method call itself again. This displays

5 from x[4]

4 from x[3]

3 from x[2]

2 from x[1]

1 from x[0]

but after displaying 1, when it tries to call the method again, an array index out of bound exception is thrown because it will try accessing an element from the array when it is already exhausted.

5 0
2 years ago
You would like to help guide your company in choosing between valuing privacy and increasing the company's bottom line. What is
Ainat [17]

In the above case, the option that will help to guide your company in choosing between valuing privacy is a set of internal principles.

<h3>What are internal control principles?</h3>

The principles of internal control are known to be  needed in the management to set methods in place to make sure that company assets are kept.

Therefore, In the above case, the option that will help to guide your company in choosing between valuing privacy is a set of internal principles.

Learn more about internal principles from

brainly.com/question/27015769

#SPJ1

6 0
2 years ago
1. How many bits would you need to address a 2M × 32 memory if:
Dominik [7]

Answer:

  1. a) 23       b) 21
  2. a) 43        b) 42
  3. a) 0          b) 0

Explanation:

<u>1) How many bits is needed to address a 2M * 32 memory </u>

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8;  L = ( 2M * 32 ) / 8 =  2M * 4

hence number of bits =  log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

<u>2) How many bits are required to address a 4M × 16 main memory</u>

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

<u>3) How many bits are required to address a 1M * 8 main memory </u>

1M = 1^1 * 1^20 ,  item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0
2 years ago
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