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Valentin [98]
2 years ago
14

Rename the number. use the place value chart to help

Mathematics
1 answer:
Blizzard [7]2 years ago
4 0
The answer is 580,000
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Unit 6: Periodic Functions and Trigonometry
Ne4ueva [31]
Just took the quiz.
A. 145°
C. /
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D. -.87,-0.5
A. Sqrt(3)/2
8 0
3 years ago
Read 2 more answers
A random sample of 40 college students has a mean earnings of​ $3120 over the summer months. Assume the population standard devi
PSYCHO15rus [73]

Answer:

A normal distribution or z-test is used to construct a confidence interval.

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = $3120

Sample size, n = 40

Population standard deviation, σ = $677

The distribution of earnings of college is a normal distribution.

Conditions:

  • Since we are given the population standard deviation and the the sample size is also greater than 30.

Conclusion:

Thus, we use a normal distribution or z-test to construct a confidence interval.

4 0
3 years ago
Can someone please help its due soon.ill give brainliest!
leva [86]

Answer:

18 and 6

4x= 18+6

4x=24

x=24/4

x=6

4x= 6×4

24

2x+3

6×2

12+3

15

3 0
2 years ago
In Brownsville Texas it is 80°F the temperature is expected to drop 1.5° each hour in Mesquite Texas is 94°F and the temperature
denis-greek [22]

Answer:

28 hours

Step-by-step explanation:

let the time period at which the temperature be equal in both Brownsville and Mesquite Texas be 'x'.

Given,

In Brownsville Texas, the temperature is expected to drop 1.5° each hour and In Mesquite Texas, the temperature is expected to drop 2° each hour.

Now, according to the question,

after 'x' hours,

⇒ 80° - 1.5°(x) = 94° - 2°(x)

⇒ 0.5°(x) = 14°

⇒ x = 28

Hence, Till 28 more hours the temperature in Mesquite Texas be greater than that in Brownsville.

3 0
3 years ago
Please help me on this TIA!!
tamaranim1 [39]
50.24 hope it helps:)
8 0
2 years ago
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