Number Line A, well the first number line.
The open circle shows us that -5 is NOT in the solution. All the numbers greater than -5 ( x > -5) are in the solution.
Faith xoxo
Answer:
The equation of plane is
Step-by-step explanation:
We have to find the equation of plane passing through the point (0,-1,1) and orthogonal to the planes
Thus, we can write:
We will evaluate:
![n = n_1\times n_2\\\\n = \left[\begin{array}{ccc}i&j&k\\3&4&-3\\-3&2&4\end{array}\right] \\\\n = i(16 + 6)-j(12-9) +k(6+12)\\n = 22i-3j+18k\\n =](https://tex.z-dn.net/?f=n%20%3D%20n_1%5Ctimes%20n_2%5C%5C%5C%5Cn%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C3%264%26-3%5C%5C-3%262%264%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5Cn%20%3D%20i%2816%20%2B%206%29-j%2812-9%29%20%2Bk%286%2B12%29%5C%5Cn%20%3D%2022i-3j%2B18k%5C%5Cn%20%3D%20%3C22%2C-3%2C18%3E)
The required plane passes through the point (0,-1,1)
Thus, the equation of plane is
is the required equation of the plane.
To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate. So in this case, divide the numerator and denominator of 70/5 by 5, to get 14/1, or 14 students per class, which is the unit rate.
To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate. So in this case, divide the numerator and denominator of 70/5 by 5, to get 14/1, or 14 students per class, which is the unit rate.
