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ANTONII [103]
3 years ago
11

Hi, umm pls help 1/6(x-5)=1/2(x+6), solve for x And can you please explain

Mathematics
1 answer:
Mumz [18]3 years ago
4 0

Answer:

By solving the equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) we found that   x=\frac{23}{2} \text { or }=11 \frac{1}{2}

<u>Explanation:  </u>

Given equation,

\frac{1}{6}(x-5)=\frac{1}{2}(x+6) to find x  

Step: 1 Cross multiply the denominators 2(x-5)=6(x+6)  

Step: 2 Open brackets and simplify the term 2x-10=6x+36  

Step: 3 Bring x terms on one side and simplify the equation the equation obtained is following,  

2x-6x=36+10

 -4x=46  

-x=\frac{46}{4}=\frac{23}{2}=11 \frac{1}{2}

Therefore, we solved x value from the given equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) as x=\frac{23}{2} \text { or }=11 \frac{1}{2}.

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weeeeeb [17]

I suppose you just have to simplify this expression.

(2ˣ⁺² - 2ˣ⁺³) / (2ˣ⁺¹ - 2ˣ⁺²)

Divide through every term by the lowest power of 2, which would be <em>x</em> + 1 :

… = (2ˣ⁺²/2ˣ⁺¹ - 2ˣ⁺³/2ˣ⁺¹) / (2ˣ⁺¹/2ˣ⁺¹ - 2ˣ⁺²/2ˣ⁺¹)

Recall that <em>n</em>ª / <em>n</em>ᵇ = <em>n</em>ª⁻ᵇ, so that we have

… = (2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺³⁾ ⁻ ⁽ˣ⁺¹⁾) / (2⁽ˣ⁺¹⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾)

… = (2¹ - 2²) / (2⁰ - 2¹)

… = (2 - 4) / (1 - 2)

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Another way to get the same result: rewrite every term as a multiple of <em>y</em> = 2ˣ :

… = (2²×2ˣ - 2³×2ˣ) / (2×2ˣ - 2²×2ˣ)

… = (4×2ˣ - 8×2ˣ) / (2×2ˣ - 4×2ˣ)

… = (4<em>y</em> - 8<em>y</em>) / (2<em>y</em> - 4<em>y</em>)

… = (-4<em>y</em>) / (-2<em>y</em>)

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