Answer:
5259544316
Step-by-step explanation:
Given that:
Length of string = 7
Either begins with 2 consonants or ends with 2 vowels :
Either or :
A U B = A + B - (AnB)
Number of vowels in alphabet = 5
Number of consonants = 21
2 consonants at beginning :
First 2 consonants, then the rest could be any:
21 * 21 * 26 * 26 * 26 * 26 * 26 = 5239686816
3 vowels at the end :
First 4 letters could be any alphabet ; last 3 should be vowels.:
26 * 26 * 26 * 26 * 5 * 5 * 5 = 57122000
2 consonants at beginning and 3 vowels at the end :
21 * 21 * 26 *26 *5* 5 * 5 = 37264500
Hence,
2 consonants at beginning + 3 vowels at end 2 consonants at beginning - 2 consonants at beginning and 3 vowels At end
(5239686816 + 57122000) - 37264500
= 5259544316
Hence, number of 7 alphabet strings that begins with 2 consonants and end with 3 vowels = 5259544316
Simplify by combining the real and imaginary parts of each expression.
1
,
−
96
Question 1:
To start off this question, we can tell that this is a square because it has 4 right angles and 4 congruent sides.
A square has four parallel sides and 4 congruent sides, so a square is a rhombus and parallelogram.
A square has 4 right angles, so it's also a rectangle.
A square has 4 sides, so it's also a quadrilateral.
The first choice is your answer.
Question 2:
Not all quadrilaterals are rectangles, so A is incorrect.
Not all quadrilaterals are squares, so B is incorrect.
All rectangles are types of quadrilaterals, so C is correct.
Not all quadrilaterals are parallelograms, so D is incorrect.
Thus, C is your answer.
Question 3:
The first choice will not work because a rhombus will satisfy those conditions, and a rhombus is not always a square.
The second choice will work because only a square will satisfy that condition because only squares have 4 congruent sides along with equal diagonals.
Thus, the second choice is your answer.
Have an awesome day! :)
The ans is3^1/3*9^1/3=27^1/3=3
