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lilavasa [31]
3 years ago
9

What percent of a sample of As-81 remains un-decayed after 43.2 seconds

Biology
1 answer:
mestny [16]3 years ago
3 0
Where Ao = starting amount, At = amount after time t, and k = rate constant 

<span>You are given that the half-life is 33 seconds </span>
<span>Calculate the rate constant </span>
<span>ln(2/1) = kx33 sec </span>
<span>0.693 = kx33 </span>
<span>k = 0.0210 s^-1 </span>

<span>Now calculate the amount left after 43.2 sec </span>
<span>ln(100%/A1%) = 0.0210 x 43.2 </span>
<span>ln(100/A1) = 0.9074 </span>
<span>100/A1 = 2.478 </span>
<span>A1 = 40.4%</span>
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