Remeber that frequency is the inverse of period length so need to get the reciprocal.
The calculated components: <-16, -12>, distance between planes: about 500 miles
The distance between two planes can be determined using two methods. We can use the formula |d2 - d1|/√ (a2 + b2 + c2) or using the point-plane distance formula.
Correct on edge2020
The angle that exists between two intersecting planes is known as a dihedral angle. In chemistry, it alludes to the angle that exists between two sets of three atoms that share two atoms.
Most commercial aircraft typically cruise at a height of between 33,000 and 42,000 feet, or roughly six and eight miles above sea level.
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Answer:
66.7 mph
Explanation:
Average speed = total distance / total time
We know the total distance is 200 miles. We need to find the total time.
During the first trip:
t = 100 mi / 100 mph
t = 1 h
During the second trip:
t = 100 mi / 50 mph
t = 2 h
So the average speed is:
s = 200 mi / 3 h
s = 66.7 mph
Round as needed.
In the above problem, we need to find mass of the second child, so that the Center of Mass remains at the origin( pivot).
CM= m1r1+m2r2/m1+m2
0= 20*-2+16*r2/20+16
r2= 40/16
r2= +2.5 m