A block of mass 1.5 hangs at the of end of a weight cord suspended from the ceiling.what is the tension in the cord, and with wh
1 answer:
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Answer:
m = 2218.67 kg
Explanation:
It is given that,
Initial velocity, u = 7.5 m/s
Final speed of an object, v = 0 (at rest)
Force, F = 5.2 kN
Time, t = 3.2 s
We need to find the mass of the object. Force acting on an object is given by :
F = ma
m is mass, a is acceleration
So, the mass of the object is 2218.67 kg
Answer:
Maximum permitted surface crack length is 1.29 mm
Explanation:
As per the question:
Tensile stress,
Surface energy of magnesium oxide, SE =
Modulus of elasticity of the material, E = 225 GPa =
Now,
To calculate the maximum allowable surface crack length:
The potential energy is defined as the energy is contained in the body due to the height over the surface of the earth and it is calculated from the equation
<em>where:</em>
- PE: the potential energy in Joules.
- m: the mass of the body in kg.
- g: the acceleration due to the gravity in m/
- h: the height of the body over the earth in meters.
<em>in our problem:</em>