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kobusy [5.1K]
3 years ago
12

Convert 1.5m squared into ft squared?​

Chemistry
1 answer:
Elodia [21]3 years ago
8 0

Answer:

24.219

Explanation:

So you multiply the area value by 10.764

1.5m² × 10.764 = 24.219

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256.3 mL + 2L + 137 mL=
Serjik [45]

Answer:

2 393.3 mL

Explanation:

(256.3 mL) + (2 L) + (137 mL) =

2 393.3 mL

3 0
4 years ago
(Thermodynamics)
Setler79 [48]

Answer:

456 kJ

Step-by-step explanation:

CH₄ + 2Cl₂ ⟶ CCl₄ + 2H₂ ; ΔH =  45.6 kJ

Treat the heat as if it were a product in the equation. Then use the molar ratio (45.6 kJ/2 mol Cl₂) in the usual way.

Amount of energy = 20 mol Cl₂ × (45.6 kJ/2 mol Cl₂)  = 456 kJ

You must add 456 kJ to react 20 mol of chlorine with excess methane.

5 0
3 years ago
How many moles of HCL are needed to react with 0.300 mol of na2 CO3​
Morgarella [4.7K]

Answer:

(b) Calculate the molarity of a solution of 4.8 mole of HCl in 600 mL of solution. ... (g) Calculate the mass of Na2CO3 that must be used to make 700 mL of a 0.136 M Na2CO3 ... (h) What mass of NaOH is needed to make 200 mL of a 0.300 M NaOH solution? ... However, when we are reacting solutions we have to convert.

Explanation:

4 0
3 years ago
Calculate the molarity of 80.0 ml of a solution that is 0.92 % by mass nacl. assume the density of the solution is the same as p
Sav [38]

<span>We are given the volume of the solution which is 80 mL or 0.08 L and the density which is equal to water, density = 1 kg / L.  Therefore calculate total mass:</span>

total mass = (1 kg / L) * (0.08 L) = 0.08 kg = 80 g

 

So the mass of NaCl is:

mass NaCl = 0.0092 * 80 g = 0.736 g

The molar mass of NaCl is 58.44 g/mol, so the number of moles is:

moles NaCl = 0.736 g / (58.44 g/mol) = 0.0126 mol

 

SO the molarity is mol / L:

<span>Molarity = 0.0126 mol / 0.08 L = 0.157 mol/L = 0.157 M</span>

6 0
3 years ago
If you are on a field trip to the ocean and you recovered 750 grams of ocean salts from a sample of ocean water, based on known
Black_prince [1.1K]
The percentage of dissolved salt in saltwater is 3.5%.  We are given the amount seawater sample. <span>We would just multiply the two values together.

750 g (0.035) = 26.25 g NaCl

26.25 g NaCl ( 1 mol / 59.44 g ) ( 1 mol Na / 1 mol NaCl ) ( 22.99 g / 1 mol ) = 10.15 g Na

Hope this answers the question. Have a nice day.</span>
3 0
4 years ago
Read 2 more answers
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