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Kipish [7]
3 years ago
14

Calculate the molarity of 80.0 ml of a solution that is 0.92 % by mass nacl. assume the density of the solution is the same as p

ure water.
Chemistry
1 answer:
Sav [38]3 years ago
6 0

<span>We are given the volume of the solution which is 80 mL or 0.08 L and the density which is equal to water, density = 1 kg / L.  Therefore calculate total mass:</span>

total mass = (1 kg / L) * (0.08 L) = 0.08 kg = 80 g

 

So the mass of NaCl is:

mass NaCl = 0.0092 * 80 g = 0.736 g

The molar mass of NaCl is 58.44 g/mol, so the number of moles is:

moles NaCl = 0.736 g / (58.44 g/mol) = 0.0126 mol

 

SO the molarity is mol / L:

<span>Molarity = 0.0126 mol / 0.08 L = 0.157 mol/L = 0.157 M</span>

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Hitman42 [59]

Answer:

W=-37.6kJ, therefore, work is done on the system.

Explanation:

Hello,

In this case, the first step is to compute the moles of each gas present in the given mixture, by using the total mixture weight the mass compositions and their molar masses:

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Next, the total moles:

n_T=0.00727kmol+0.00625kmol+0.0139kmol=0.02742kmol

After that, since the process is isobaric, we can compute the work as:

W=P(V_2-V_1)

Therefore, we need to compute both the initial and final volumes which are at 260 °C and 95 °C respectively for the same moles and pressure (isobaric closed system)

V_1=\frac{n_TRT_1}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(260+273)K}{450kPa}=0.27m^3\\ \\V_2=\frac{n_TRT_2}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(95+273)K}{450kPa}=0.19m^3

Thereby, the magnitude and direction of work turn out:

W=450kPa(0.19m^3-0.27m^3)\\\\W=-37.6kJ

Thus, we conclude that since it is negative, work is done on the system (first law of thermodynamics).

Regards.

7 0
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