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ladessa [460]
3 years ago
7

A rectangle's length is 3 feet longer than its width. its perimeter is 62 feet

Mathematics
1 answer:
DanielleElmas [232]3 years ago
6 0

Hi!

<h3>The perimeter is equal to </h3>

<u>l + l + w + w = 62</u>

<h3>The length is 3 feet longer than the width so...</h3>

<u>w + 3 + w + 3 + w + w = 62</u>

<h3>Simplify</h3>

<u>4w + 6 = 62</u>

4w + 6 - 6 = 62 - 6

4w = 56

4w/4 = 56/4

<u>w = 14</u>

<u>14 + 3 = 17</u>

<h2>The width is 14 and the length is 17. </h2>

Hope this helps! :)

-Peredhel

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\begin{gathered} OX^2=XY^2+OY^2 \\ 10^2=5^2+OY^2 \\ 100=25+OY^2 \\ OY^2\text{ = 100 -25} \\ OY^2\text{ = 75} \\ OY\text{ = }\sqrt[]{75} \\ OY\text{ = }\sqrt[]{25\text{ }\times\text{ 3}} \\ OY\text{ = 5}\sqrt[]{3\text{ }}in \end{gathered}

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