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torisob [31]
3 years ago
15

to determine a student's grade, a teacher throws out the lowest grade obtained on 5 tests, averages the remaining grades, and ro

und up to the nearest interger. If Betty scored 75,90,88,72,and86 on her tests, what grade will she receive​
Mathematics
2 answers:
jekas [21]3 years ago
8 0

Answer:

Betty will get 85 grade.

Step-by-step explanation:

Betty scored 75,90,88,72, and 86 on her tests.

As given the teacher throws out the lowest grade, we will not consider 72.

Now the teacher averages the remaining grades, and round up to the nearest integer.

So, taking the average we get;

\frac{75+90+88+86}{4}

= 84.75

Rounding this to nearest integer, we get 85.

Hence, Betty will get 85 grade.

RoseWind [281]3 years ago
3 0

Answer:

B grade

Step-by-step explanation:

75 + 90 + 88 + 86 = 339

339/4 = 84.75

Grade B = 80-89%

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Step-by-step explanation:

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3 years ago
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b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
3 years ago
Suppose PR = 54, solve for QR<br> 4x-1<br> 3x-1<br> P<br> R
Svet_ta [14]

Answer:

QR = 23

Step-by-step explanation:

P, A, and R are collinear.

PR = 54

PQ = 4x - 1

QR = 3x - 1

To solve for the numerical length of PR, let's generate an equation to find the value of x.

According to the segment addition postulate:

PQ + QR = PR

(4x - 1) + (3x - 1) = 54 (substitution)

Solve for x

4x - 1 + 3x - 1 = 54

Combine like terms

4x + 3x - 1 - 1 = 54

7x - 2 = 54

Add 2 to both sides

7x - 2 + 2 = 54 + 2

7x = 56

Divide both sides by 7

\frac{7x}{7} = \frac{56}{7}

x = 8

QR = 3x - 1

Plug in the value of x into the equation

QR = 3(8) - 1 = 24 - 1

QR = 23

5 0
3 years ago
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