The given equality hold true when x = 2.
Put x = 2 in inequality.
2(2) + 3 = 4+3 = 7 = R.H.S.
For x = 4 and 6, L.H.S(2x+3) is greater than 7.
Hence for x = 2, 4 and 6, the above inequality holds true.
Hope this helps!
Answer:
#1 is -9
#2 is 3
Step-by-step explanation:
-9x3 is -27 then add 10 to that you get -17
5x3 is 15 then subtract 1 and you get 14
A) x + y = 24
B) x^2 + y^2 = 306
A) x = 24 -y
Then substituting this into B)
(24 - y)^2 +y^2 = 306
576 -48y +y^2 + y^2 = 306
2 y^2 -48y + 270 = 0
x1 = 15
x2 = 9
