Answer:
it is proved that from the any three consecutive integers one of them is divisible by 3.
Step-by-step explanation:
Let the first integer = x
The second consecutive integer = x + 1
The third consecutive integer = x + 2
Case 1. take x = 1
The value of first integer = 1
The value of second integer = 1 +1 = 2
The value of third integer = 1 + 2 = 3
Here the third integer is divisible by 3.
Case 2. take x = 2
The value of first integer = 2
The value of second integer = 2 +1 = 3
The value of third integer = 2 + 2 = 4
Here the second integer is divisible by 3.
Case 3. take x = 3
The value of first integer = 3
The value of second integer = 3 +1 = 4
The value of third integer = 3 + 2 = 5
Here the first integer is divisible by 3.
Thus it is proved that from the any three consecutive integers one of them is divisible by 3.
