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Butoxors [25]
3 years ago
15

The GCF of 18 and 30 is

Mathematics
2 answers:
stepladder [879]3 years ago
7 0

Answer: 6

Step-by-step explanation:

denis23 [38]3 years ago
3 0

Answer:

The answer is 6, 6 is the GCF

Step-by-step explanation:

6 is the the Greatest Common Factor (GCF) because 6 can go into both numbers 18 and 30 evenly, 6 can multiply with 3 for the product to be 18 and 6 can multiply with 6 for the product to be 30. I hope this help.    :  )

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4,400 is 10 times as much as 440
snow_lady [41]
True. Because if you multiply 440 by 10, the answer is 4,400. So 4,400 is 10 times as much as 440.
To each number multiplied by 10, the answer is the same number with an additional zero to the right.

Hope this Helps! :)
7 0
3 years ago
Expand.<br> Your answer should be a polynomial in standard form.<br> (x-3)(x-4)=
nekit [7.7K]

Answer:

Step-by-step explanation:

So, it's x*x+x*-3+-4*x+3*-3

That simplifies to x^2 - 7x + 12

5 0
2 years ago
Combine like terms to create an equivalent expression -4/7p+(-2/7p)+1/7
STatiana [176]
-6/7p+1/7 um Idk what you wanted me to do but I added -4/7p with -2/7p
7 0
3 years ago
Read 2 more answers
Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y
professor190 [17]

Answer:

Required total charge is 256\pi coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

x^2=y^2\leq 16 so that the charge density at (x,y) is,

\rho (x,y)=2x+2y+2x^2+2y^2

To find total charge on the disk let Q be the total charge and x=r\cos\theta,y=r\sin\theta so that,

Q={\int\int}_Q\rho(x,y) dA                where A is the surface of disk.

=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA

=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta

=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta

=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta

=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta

=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi

=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi

=256\pi

Hence total charge is 256\pi coulombs per square meter.

3 0
3 years ago
List the following objects in order from lowest inertia to highest inertia: Earth, desk, baseball, fork, house, feather,
kirill115 [55]

Answer:

Feather, fork, baseball, desk, cow, tow truck, house, Earth, Sun

Step-by-step explanation:

The bigger the object, the more inertia it has, since it's harder to move a bigger object. So, since a feather is the smallest thing with the least amount mass, it should be the easiest to move, giving it the least amount of inertia. It's the opposite for the Sun, since it's the biggest object on the list.

3 0
3 years ago
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