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irina [24]
3 years ago
14

A car collides head on with a stationary sign. The collision brings the car to a stop, but the sign does not move.

Physics
1 answer:
olga_2 [115]3 years ago
7 0

A.a sign that breaks loose from the ground when a force is applied to it

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A grocery cart of mass 16 kg is being pushed at a constant speed up a 12-degree ramp by a force of [{MathJax fullWidth='false' f
lawyer [7]

Answer:

If the cart is being pushed at a constant speed, then the acceleration in the direction of motion is zero. Hence, the force in the direction of the motion is zero, according to Newton's Second Law.

\Sigma F_x = ma_x

For simplicity, I will denote the direction along the inclined ramp as x-direction.

In the question the value of the force is not clearly given, so I will denote it as F_P

\Sigma F_{net_x} = ma_x\\\Sigma F = F_{P}\cos(29^\circ) - mg\sin(12^\circ) = ma_x = 0\\F_{P}\cos(29^\circ) = mgsin(12^\circ)\\F_{P}\times 0.8746 = 16\times 9.8\times  0.2079\\F_{P} = 37.2740

Here the angle between the applied force and the x-direction is 12° + 17° = 29°

The x-component of the weight of the cart is equal to sine component of the weight.

Since the cart is rolling on tires the kinetic friction does no work.

Work done by the applied force:

W_{F_P} = F_P_x \cos(29^\circ)\times 7.5 = 244.5 ~J

Work done by the weight of the cart:

W_{mg} = -mg\sin(12^\circ)\times 7.5 = -16\times 9.8 \times 0.2079 \times 7.5 = - 244.5~J

Since the x-component of the weight is in the -x-direction, its work is negative.

Conveniently, the total work done on the particle is zero, since its velocity is constant.

5 0
3 years ago
Imagine that two charged objects are the system of interest. When the objects are infinitely far from each other, the electric p
podryga [215]

Answer: Option (c) is the correct answer.

Explanation:

It is known that the expression for potential energy related to charges and distance between their separation is as follows.

           U_{q} = \frac{kq_{1}q_{2}}{r}  

where,   q_{1} and q_{2} are two charges

                r = distance of separation between the charges

               k = electrostatic constant

So, when both the charges are carry the same charge and r is small then the value of potential energy will be positive in nature.

Whereas if the distance of separation between the charges is infinitely large then the potential energy calculated will be zero everywhere.

Thus, we can conclude that the statement one object is negatively charged and the other one is positively charged, is incorrect.

5 0
3 years ago
Match each prefix to the correct multiple of 10. 1. centi- 10 2. kilo- 100 3. deka- 1000 4. milli- 1/100 5. hecto- 1/10 6. deci-
Mice21 [21]

Explanation :

There are some basic metric conversions.

Prefix                   Multiple of 10

centi                            \frac{1}{100}

Kilo                              1000

deka                              10

milli                              \frac{1}{1000}

hecto                            100

deci                              \frac{1}{10}

For example :

1cm=\frac{1}{100}m\\\\1Km=1000m\\\\1mm=\frac{1}{1000}m\\\\1Km=10\text{ hecto meter}\\\\1Km=100\text{ deka meter}


7 0
3 years ago
Read 2 more answers
If the current in a wire is 2.0 amperes and the potential difference across the wire is 10.0 volts, what is the resistance of th
avanturin [10]

Answer:

v=IR

10÷2 =R

R=5 Ohm

.. .

4 0
3 years ago
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The diagram shows the set-up for an electric doorbell. At bottom, a doorbell. Starting from midright, a wire attached to a conta
mylen [45]

Answer:

the answer is that the circuit is open,

Explanation:

if you look towards the switch its off, or open meaning no current can flow

6 0
3 years ago
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