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aksik [14]
3 years ago
5

Why is it okay to have a radioactive alpha source in a smoke detector in your house?

Physics
1 answer:
egoroff_w [7]3 years ago
5 0
When smoke particles pass between the source of radiation and the detector the drop in radiation will be sufficient to tigger the alarm. <span />
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A test charge of +2μC is placed halfway between a charge of +6μC and another of +4μC separated by 10 cm. (a) What is the magnitu
Nady [450]

Answer:

Part a)

F = 14.4 N

Part b)

away from +6μC charge

Explanation:

Force on the charge placed midway between two charges is given by

F = \frac{kq_1q}{r^2} - \frac{kq_2q}{r^2}

here we know that

q = 2\mu C

q_1 = 6 \mu C

q_2 = 4\mu C

here the charge is placed at mid point so we have

r = 5 cm

now we have

F = \frac{(9\times 10^9)(6\mu C)(2\mu C)}{0.05^2} - \frac{(9\times 10^9)(2\mu C)(4\mu C)}{0.05^2}

F = 43.2 - 28.8 = 14.4 N

Part b)

since +6μC charge is more in magnitude so the force due to this charge will be more so the net force on it is away from +6μC charge

8 0
4 years ago
Explain how the air balloon moves up and down.<br> Explain in terms of density
Fantom [35]
The heat in the air ballon from the flame will create moisture in the ballon and make it rise
4 0
3 years ago
Which one of the following scenarios accurately describes a condition in which resonance can occur?
mr Goodwill [35]
A pipe's length is equal to 1⁄2 of the wavelength of the sound waves produced by a tuning fork vibrating over one end of the pipe that's open to the air at both ends.
4 0
4 years ago
Can someone answer this question quickly??
masya89 [10]

Answer:

Lithium and Sodium

Explanation:

Lithium and Sodium is in the same group 1A

7 0
3 years ago
On a horizontal frictionless surface a mass M is attached to two light elastic strings both having length l and both made of the
EastWind [94]

Answer:

ω = √(2T / (mL))

Explanation:

(a) Draw a free body diagram of the mass.  There are two tension forces, one pulling down and left, the other pulling down and right.

The x-components of the tension forces cancel each other out, so the net force is in the y direction:

∑F = -2T sin θ, where θ is the angle from the horizontal.

For small angles, sin θ ≈ tan θ.

∑F = -2T tan θ

∑F = -2T (Δy / L)

(b) For a spring, the restoring force is F = -kx, and the frequency is ω = √(k/m).  (This is derived by solving a second order differential equation.)

In this case, k = 2T/L, so the frequency is:

ω = √((2T/L) / m)

ω = √(2T / (mL))

6 0
3 years ago
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