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2 years ago

Plz help me with this

Mathematics

2 answers:

madreJ [45]2 years ago

6 0

In order a0->a5: 1/3, 1, 3, 9, 27, 81

All you're doing is plugging the x-value in. So for a2, x=1, so y=3¹ which means y=3.

Andrews [41]2 years ago

4 0

Answer: $\bold{\dfrac{1}{3}}$ , 1, 3, 9, 27, 81

Step-by-step explanation:

$\left\begin{array}{c|l}\underline{\quad x\quad} &\underline{3^x=y}\\-1&3^{-1}=\frac{1}{3}\\0&3^0=1\\1&3^1=3\\2&3^2=9\\3&3^3=27\\4&3^4=81\end{array}\right$

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What is the slope of the line that passes through the given points (6,-1) and (-3,-1)

vaieri [72.5K]

Hello : let A(6,-1) B(-3,-1)
the slope is : (YB - YA)/(XB -XA)
(-1+1)/(-3+6) = 0
the slope is : 0 ...(answer : B.) 0 )

8 0

2 years ago

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Find the discriminant, and determine the number of real solutions. then solve x^2 +8x+20=0

vodomira [7]

Answer:

Part 1) The quadratic equation has zero real solutions

Part 2) The solutions are

$x_1=-4+2i$ and $x_2=-4-2i$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}+8x+20=0$

$a=1\\b=8\\c=20$

The discriminant is equal to

$D=(b^{2}-4ac)$

If D=0 -----> the quadratic equation has only one real solution

If D>0 -----> the quadratic equation has two real solutions

If D<0 -----> the quadratic equation has two complex solutions

Find the value of D

$D=8^{2}-4(1)(20)=-16$ -----> the quadratic equation has two complex solutions

Find out the solutions

substitute the values of a,b and c in the formula

$x=\frac{-8(+/-)\sqrt{8^{2}-4(1)(20)}} {2(1)}$

$x=\frac{-8(+/-)\sqrt{-16}} {2}$

Remember that

$i=\sqrt{-1}$

$x=\frac{-8(+/-)4i} {2}$

$x_1=\frac{-8(+)4i} {2}=-4+2i$

$x_2=\frac{-8(-)4i} {2}=-4-2i$

8 0

3 years ago

Idk how to do this someone help me

Vlad [161]

I'm thinking its 4 to the 12 power but I am not completely sure on this

4 0

2 years ago

Read 2 more answers

ACDF is a trapezoid and

Sholpan [36]

Answer:

x = 7

Step-by-step explanation:

See the attached figure.

As shown: A C D F is a trapezoid and BE is a mid-segment.

The mid-segment of the trapezoid is the average of its bases.

BE = 0.5 ( A F + C D)

Given: CD = 18 , BE = 2x + 10 and A F = 6x - 12

So,

2x + 10 = 0.5 ( 18 + 6x - 12)

Solve for x

2x + 10 = 0.5 (6 + 6x)

2x + 10 = 3 + 3x

10 - 3 = 3x - 2x

∴ x = 7

So, the value of x is 7

8 0

2 years ago

Last one - Thank you an advance :)

Ivan

Answers:
a. Given
b. Transitive property of congruence
c. Vertical angles are congruent
d. Transitive property of congruence

Let me know if you need any clarification as to how I got those answers. They should be self-explanatory but I'm happy to clarify further if needed.

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2 years ago

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