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soldier1979 [14.2K]

3 years ago

15

(07.06) Which of the following graphs shows all the possible values for a number that is less than 7? Number line with closed ci

rcle on 7 and shading to the left. Number line with closed circle on 7 and shading to the right. Number line with open circle on 7 and shading to the left. Number line with open circle on 7 and shading to the right.

2 answers:

hodyreva [135]3 years ago

8 0

The answer is "a number line with an open circle and shading to the left"

alexgriva [62]3 years ago

8 0

Answer:

It is the third on ethe open ciricle on 7 going all the way to the left

Step-by-step explanation:

I got this question right on my exam

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Please help!! QUESTION IS BELOW

Andrew [12]

Answer:

Step-by-step explanation:

√((5-1)²+ (4 - (-6))²

√(4)² + (10)²

√(16+100)

√116

2√(29)

8 0

2 years ago

Find the final price or each product after sales tax is applied. Round to the nearest cent. Potted Plant: $17.29 Sales Tax: 3%

Margaret [11]

Answer:

17.81 would be your answer.

Step-by-step explanation:

You would do 17.29 x 1.03 to get the price after sales tax is added which would be 17.81

4 0

3 years ago

Please help me thanks please

Ludmilka [50]

Answer: 3234 cubic units

Step-by-step explanation:

Volume of cylinder: πr²h

The diameter of the cylinder is 14 units so the radius is 7 units.

Now we'll substitute.

π = 22/7

h = 21

πr²h

π × 7² × 21

22/7 × 49 × 21 = 3,234

The volume is 3,234 cubic units.

6 0

3 years ago

John has $20.43 dollars in his pocket. He buys a tv for $15.39 dollars. How many dollars does John have left?

AleksAgata [21]

All you do is subtract what John is spending from the amount he has. 20.43-15.39= $5.04

4 0

3 years ago

A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level, hence $\alpha = 0.9$ , z is the value of Z that has a p-value of $\frac{1+0.9}{2} = 0.95$ , so $z = 1.645$ .

Item a:

The estimate is $\pi = 0.213 - 0.195 = 0.018$ .

The sample size is <u>n for which M = 0.03</u>, hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}$

$0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}$

$\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2$

$n = 53.1$

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence $\pi = 0.05$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}$

$0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2$

$n = 751.7$

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0

2 years ago