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2 years ago

the number of people with one type of flu doubles every day for several days what type of function represents this pattern

Mathematics

2 answers:

svet-max [94.6K]2 years ago

8 0

Answer:

The answer will be Exponential growth.

<em>Please mark me as the brainliest.</em>

alexandr402 [8]2 years ago

5 0

Answer:

exponential growth

Step-by-step explanation:

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PLEASE HELP ME!!! WILL GIVE BRAINLIEST! PLEASE IT SHOULD BE EASY FOR SOMEONE WHO ISNT SUPER SICK!! Please

ArbitrLikvidat [17]

Answer:

D is the answer.

Step-by-step explanation:

You can see if a line is perpendicular by the slope. If the slope is COMPLETELY opposite from another by means of slope, the lines are perpendicular.

-1/4

4/1

...are opposite.

5 0

3 years ago

8. Combine the like terms in this expression: –3x + 2xy + 4y – xy + 2x – 11y

luda_lava [24]

Answer:

D. –X+XY–7y

Step-by-step explanation:

We just have to combine (add) the similar terms... so all terms that have an x in them for example.

–3x + 2xy + 4y – xy + 2x – 11y

Let's first re-write it placing similar terms next to each other

(-3x + 2x) + (2xy - xy) + (4y - 11y)

Then we sum them up, for each similar terms

1x + 1xy -7y

so, x + xy -7y

Answer D.

6 0

3 years ago

How many centimeters are in 1 meter

WARRIOR [948]

100 centimeter in a meter
100*1=100

3 0

3 years ago

Read 2 more answers

When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F

aleksandr82 [10.1K]

Let $x$ be the unknown number. So, three times that number means $3x$ , and the square of the number is $x^2$

We have to sum 528 and three times the number, so we have $528+3x$

Then, we have to subtract this number from $x^2$ , so we have

$x^2-(3x+528)$

The result is 120, so the equation is

$x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0$

This is a quadratic equation, i.e. an equation like $ax^2+bx+c=0$ . These equation can be solved - assuming they have a solution - with the following formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

If you plug the values from your equation, you have

$x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}$

So, the two solutions would be

$x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27$

$x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24$

But we know that x is positive, so we only accept the solution $x = 27$

6 0

3 years ago

The altitude of a triangle is increasing at a rate of 1 cm/ min while the area of the triangle is increasing at a rate of 2 cm2

serg [7]

Ya, calculus and related rates, such fun!

everything is changing with respect to t

altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min

area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min

base=db/dt

alright

area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt

ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b

so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min

therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt

the base is decreasing at 1.6cm/min

4 0

3 years ago