Question

A presidential candidate plans to begin her campaign by visiting the capitals in 4 of 42 states. What is the probability that she selects the route of four specific​ capitals? ​P(she selects the route of four specific ​capitals)equals nothing

Answer 1

Answer:

P(she selects the route of four specific ​capitals) = 1 in 2,686,320 or 3.72 x 10⁻⁷

Step-by-step explanation:

Assuming that the order at which she visits each of the four cities matters, the number of possible routes is the permutation of choosing 4 out of 42 capitals:

$n=\frac{42!}{(42-4)!}\\n=42*41*40*39\\n=2,686,320\ ways$

Therefore, the probability that she selects the route of four specific capitals is 1 in 2,686,320 or 3.72 x 10⁻⁷