Answer:
The answer is cosx cot²x ⇒ the first answer
Step-by-step explanation:
∵ cot²x = cos²x/sin²x
∵ secx = 1/cosx
∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx
= (cosx/sin²x) - cosx
Take cosx as a common factor
∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M
∴ cosx[1-sin²x/sin²x]
∵ 1 - sin²x = cos²x
∴ cosx(cos²x/sin²x) = cosx cot²x
Answer:
1
Step-by-step explanation:
2/4 + 1/2 = 1
Hope this helps you!
Are there any choices that i can help with to solve the work problem
Answer:
9 remainder 1
Step-by-step explanation:
Not sure but uh... 73/8=9 remainder 1.
Is this what you are looking for?
