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vitfil [10]
2 years ago
10

Write the slope-intercept form of the equation of the line described by (−1, −1), parallel to y = −2x − 4

Mathematics
1 answer:
LuckyWell [14K]2 years ago
7 0

Answer:

y = -2x - 3

Step-by-step explanation:

Slope intercept form of line is

y = mx + c

where

m is the slope and c is the y intercept

________________________________________

Given that line

y = −2x − 4

comparing it with y = mx + c

m = -2 and c = -4

Thus, slope of this line is -2

we also know that when two lines are parallel then their slopes are same

thus, slope of required line will be m = -2

___________________________________________

now let the equation of line passing through (-1,-1) be

y = mx + c

we have found m to be -2

using this in above equation we have

y = -2x + c

since (-1,-1) passes through the above line using x = -1 and y = -1

we have

-1 = -2*-1 + c

-1 = 2 + c

c = -1 - 2 = -3

using c = -3 in y = -2x + c

we have

equation of line as

y = -2x - 3 in slope intercept form.

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What is the slope-intercept form of the equation of a line that passes through (5, -4) and has a slope of 34?
Alla [95]
One way to find the slope-intercept form is to plug the given values into point-slope form, y - y_{1} = m (x - x_{1}), where x_{1} and y_{1} are the coordinate points and m is the slope. Then, you solve for y.

y - y_{1} = m (x - x_{1})   Plug in the values
  y - (-4) = 34 (x - 5)         Fix the minus negative four
     y + 4 = 34 (x - 5)         Use the Distributive Property
     y + 4 = 34x - 170        Subtract 4 from both sides
           y = 34x - 174

The slope-intercept form of the equation that passes through (5, -4) and has a slope of 34 is y = 34x - 174.

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levacccp [35]
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3 years ago
The curve with equation y=ax^2+bx has a gradient of 3 at the point (2,-2). Find the values of a and b.
Airida [17]

Answer:

a = 2, b = - 5

Step-by-step explanation:

Given

y = ax² + bx

\frac{dy}{dx} is the measure of the slope at x = a

Differentiate each term with respect to x using the power rule

\frac{d}{dx}(ax^{n} ) = nax^{n-1}

\frac{dy}{dx} = 2ax + b, hence

2ax + b = 3 at (2, - 2)

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4a + 2b = - 2 → (2)

Subtract ( 1) from (2)

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Substitute b = - 5 into (1)

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Answer:

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Step-by-step explanation:

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